Android-防止按钮在PopupWindow外部单击 [英] Android - Prevent button click outside of PopupWindow
本文介绍了Android-防止按钮在PopupWindow外部单击的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我花了一段时间尝试使它生效,并在网上寻找类似的解决方案,但似乎没有一个可行.我只需要单击生成"按钮就可以关闭我的PopupWindow,而不必单击窗口外部.有人遇到过这个问题吗?
I've spent a while trying to get this to work, looked for similar solutions online, but none seem to work. I need my PopupWindow to only be dismissed on the click of the generate button, not by clicking outside the window. Anyone encountered this issue before?
private void LoadRAMSPopup() {
mainLayout.getForeground().setAlpha(150);
LayoutInflater layoutInflater = (LayoutInflater) getBaseContext().getSystemService(LAYOUT_INFLATER_SERVICE);
final View ramsView = layoutInflater.inflate(R.layout.popup_rams, null);
final PopupWindow popupRAMS = new PopupWindow(
ramsView,
ViewGroup.LayoutParams.WRAP_CONTENT,
ViewGroup.LayoutParams.WRAP_CONTENT
);
if (Build.VERSION.SDK_INT >= 21) {
popupRAMS.setElevation(5.0f);
}
findViewById(R.id.mainLayout).post(new Runnable() {
@Override
public void run() {
popupRAMS.showAtLocation(findViewById(R.id.mainLayout), Gravity.CENTER, 0, 0);
popupRAMS.setOutsideTouchable(false);
popupRAMS.setFocusable(true);
popupRAMS.update();
Button btnGenerate = (Button) ramsView.findViewById(R.id.btnGenerate);
btnGenerate.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
Intent intent = new Intent(getApplicationContext(), CreateRAMSActivity.class);
startActivity(intent);
popupRAMS.dismiss();
mainLayout.getForeground().setAlpha(0);
}
});
}
});
}
推荐答案
设置 popupRAMS.setFocusable(false).删除使弹出窗口消失所需的不必要的触摸.所以请更换
Setting up popupRAMS.setFocusable(false). removes unnecessary touch required to make popup window disappear. So please replace
popupRAMS.setFocusable(true);
与
popupRAMS.setFocusable(false);
也尝试添加
popupRAMS.setOutsideTouchable(false);
希望它会对您有所帮助.
Hope it will help you out.
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