Python:绑定套接字:“地址已在使用中" [英] Python: Binding Socket: "Address already in use"

问题描述

我对TCP/IP网络上的客户端套接字有疑问.假设我使用

I have a question regarding client socket on TCP/IP network. Let's say I use

try:

    comSocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
    comSocket.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)

except socket.error, msg:

    sys.stderr.write("[ERROR] %s\n" % msg[1])
    sys.exit(1)

try:
    comSocket.bind(('', 5555))

    comSocket.connect()

except socket.error, msg:

    sys.stderr.write("[ERROR] %s\n" % msg[1])

    sys.exit(2)

创建的套接字将绑定到端口5555.问题在于结束连接后

The socket created will be bound to port 5555. The problem is that after ending the connection

comSocket.shutdown(1)
comSocket.close()

使用wireshark，我看到套接字从两侧用FIN，ACK和ACK闭合，我无法再使用该端口.我收到以下错误:

Using wireshark, I see the socket closed with FIN,ACK and ACK from both sides, I can't use the port again. I get the following error:

[ERROR] Address already in use

我想知道如何立即清除端口，以便下次仍可以使用该端口.

I wonder how can I clear the port right away so that next time I still can use that same port.

comSocket.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)

setsockopt似乎无法解决问题 谢谢！

setsockopt doesn't seem to be able to resolve the problem Thank you!

推荐答案

在绑定套接字之前尝试使用SO_REUSEADDR套接字选项.

Try using the SO_REUSEADDR socket option before binding the socket.

comSocket.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)

修改: 我看到您仍然对此感到麻烦.在某些情况下，SO_REUSEADDR将不起作用.如果尝试绑定套接字并重新连接到相同的目的地(启用SO_REUSEADDR)，则TIME_WAIT仍然有效.但是，它将允许您连接到其他主机:端口.

I see you're still having trouble with this. There is a case where SO_REUSEADDR won't work. If you try to bind a socket and reconnect to the same destination (with SO_REUSEADDR enabled), then TIME_WAIT will still be in effect. It will however allow you to connect to a different host:port.

想到了几种解决方案.您可以继续重试，直到可以重新获得连接为止.或者，如果客户端启动套接字(而不是服务器)的关闭，那么它应该可以神奇地工作.

A couple of solutions come to mind. You can either continue retrying until you can gain a connection again. Or if the client initiates the closing of the socket (not the server), then it should magically work.

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