发布到Django Rest框架 [英] Post to django rest framework

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本文介绍了发布到Django Rest框架的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想使用post发布到我的Django服务器,以便添加todo项目.这是模型:

I'd like to post to my Django server using post so I can add a todo item. Here is the model:

class Todo(models.Model):
    title = models.CharField(max_length=200);
    text = models.TextField()
    completed = models.BooleanField(default=False)
    created_at = models.DateTimeField(default=datetime.now, blank = True )
    def __str__(self):
        return self.title

和序列化器:

class TodoSerializer(serializers.ModelSerializer):
    class Meta:
        model = Todo
        fields = ("id", 'title','text', 'completed', 'created_at')

然后查看:

class TodoList(APIView):
    def get(self,request):
        todo=Todo.objects.all()
        serializer=TodoSerializer(todo,many=True)
        return Response(serializer.data)
    def post(self,request):
        Todo.objects.create(
            title=request.POST.get('title'),
            text=request.POST.get('text'))
        return HttpResponse(status=201)

我的帖子请求是

{ "title": "new title",
  "text": "a test text"}

它告诉我

IntegrityError at /todos/
(1048, "Column 'title' cannot be null")

作为Django的新手,我不了解此错误.有什么想法吗?

As a newbie at Django, I don't understand this error. Any ideas?

推荐答案

您需要访问request.data而不是request.POST

def post(self,request):
    serializer = TodoSerializer(data=request.data)
    if serializer.is_valid():
        serializer.save()
        return Response(serializer.data, status=status.HTTP_201_CREATED)
    return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)

这篇关于发布到Django Rest框架的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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