如何使用改造2发出POST请求? [英] How to make a POST request using retrofit 2?
问题描述
我只能从文档中运行hello world示例(GithubService).
I was only able to run the hello world example (GithubService) from the docs.
问题是当我运行代码时,在onFailure()
The problem is when I run my code, I get the following Error, inside of onFailure()
使用JsonReader.setLenient(true)在第1行接受格式错误的JSON 第1列路径$
Use JsonReader.setLenient(true) to accept malformed JSON at line 1 column 1 path $
我的API采用POST参数值,因此无需将其编码为JSON,但确实会以JSON返回响应.
My API takes POST params value, so no need to encode them as JSON, but it does return the response in JSON.
对于响应,我获得了使用工具生成的ApiResponse类.
For the response I got ApiResponse class that I generated using tools.
我的界面:
public interface ApiService {
@POST("/")
Call<ApiResponse> request(@Body HashMap<String, String> parameters);
}
这是我使用服务的方式:
Here is how I use the service:
HashMap<String, String> parameters = new HashMap<>();
parameters.put("api_key", "xxxxxxxxx");
parameters.put("app_id", "xxxxxxxxxxx");
Call<ApiResponse> call = client.request(parameters);
call.enqueue(new Callback<ApiResponse>() {
@Override
public void onResponse(Response<ApiResponse> response) {
Log.d(LOG_TAG, "message = " + response.message());
if(response.isSuccess()){
Log.d(LOG_TAG, "-----isSuccess----");
}else{
Log.d(LOG_TAG, "-----isFalse-----");
}
}
@Override
public void onFailure(Throwable t) {
Log.d(LOG_TAG, "----onFailure------");
Log.e(LOG_TAG, t.getMessage());
Log.d(LOG_TAG, "----onFailure------");
}
});
推荐答案
如果您不希望使用JSON编码的参数,请使用以下方法:
If you don't want JSON encoded params use this:
@FormUrlEncoded
@POST("/")
Call<ApiResponse> request(@Field("api_key") String apiKey, @Field("app_id") String appId);
这篇关于如何使用改造2发出POST请求?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!