来自PHP的HTTP POST，无cURL [英] HTTP POST from PHP, without cURL

问题描述

我正在使用此中提供的示例函数帖子:

<?php
function do_post_request($url, $data, $optional_headers = null)
{
  $params = array('http' => array(
              'method' => 'POST',
              'content' => $data
            ));
  if ($optional_headers !== null) {
    $params['http']['header'] = $optional_headers;
  }
  $ctx = stream_context_create($params);
  $fp = @fopen($url, 'rb', false, $ctx);
  if (!$fp) {
    throw new Exception("Problem with $url, $php_errormsg");
  }
  $response = @stream_get_contents($fp);
  if ($response === false) {
    throw new Exception("Problem reading data from $url, $php_errormsg");
  }
  return $response;
}
?>

我还尝试了使用file_get_contents()的类似方法，如下所示:

I also tried a similar approach using file_get_contents(), like this:

$options = array(
  'http'=>array(
    'method'=>"POST",
    'header'=>
      "Accept-language: en\r\n".
      "Content-type: application/x-www-form-urlencoded\r\n",
    'content'=>http_build_query(
        array(
            'arg1'=>'arg_data_1',
            'oper'=>'get_data',
            'arg2'=>'arg_data_2',
            'id_number'=>'7862'
        ),'','&'
    )
));

$context = stream_context_create($options);
$refno = file_get_contents('/path/to/script/script.php',false,$context);

var_dump($refno);

使用这两个脚本，服务器脚本的响应是相同的，并且是script.php的TEXT.服务器脚本的代码永远不会开始执行，并且脚本的文本内容(PHP代码)将返回到原始脚本.

With both these scripts, the response from the server script is the same, and it is the TEXT of the script.php. The code of the server script is never begin executed, and the text content (the PHP code) of the script is being returned to the original script.

有些奇怪，它不会返回所有文本，而只是返回某些片段...我试图制作一个仅包含以下内容的测试脚本(test.php)

A little strange that it doesn't return all the text, but just certain pieces... I tried making a test script (test.php) that just contains:

<?php
echo '{"a":1,"b":2,"c":3,"d":4,"e":5}';
?>

但这从POST请求中不返回任何内容，因此我没有包含该内容. script.php是一个必须更长的脚本，它执行很多逻辑，MySQL查询然后返回一个JSON对象.

but that doesn't return anything from the POST request, so I didn't include that. The script.php is a must longer script that does a lot of logic and MySQL queries then returns a JSON object.

所需的输出将是使PHP代码执行并返回JSON对象(与ajax一起工作的方式).

The desired output will be to have the PHP code execute and return a JSON object (the way it works with ajax).

我在做什么错了?

推荐答案

您正在尝试访问脚本语言环境. 您必须像其他任何外部脚本一样调用它

You are trying access script localy. You must call it like any other external script like

$refno = file_get_contents('http://yourhost/path/to/script/script.php',false,$context);

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