C#建立一个接受POST方法(例如HttpWebRequest方法)的websevice方法 [英] C# build a websevice method that accepts POST methods like HttpWebRequest method
问题描述
我需要一个可以接受POST方法的Web服务.正在访问我的服务器正在使用POST方法. 它向我发送了一个xml，我应该用一些xml进行响应.
i need a web service that accepts POST methods. An server that is accessing me is using POST method. It sends me an xml and i should response with some xml.
相反，当我访问他时，我已经使用HttpWebRequest类进行了管理，并且工作正常.它是这样完成的:
The other way, when i'm accessing him, i have managed with HttpWebRequest class and it works fine. It is done like:
HttpWebRequest req = (HttpWebRequest)WebRequest.Create(s.strMvrataUrl.ToString());
req.ClientCertificates.Add(cert);
req.Method = "POST";
req.ContentType = "text/xml; encoding='utf-8'";
s.AddToLog(Level.Info, "Certifikat dodan.");
byte[] bdata = null;
bdata = Encoding.UTF8.GetBytes(strRequest);
req.ContentLength = bdata.Length;
Stream stremOut = req.GetRequestStream();
stremOut.Write(bdata, 0, bdata.Length);
stremOut.Close();
s.AddToLog(Level.Info, "Request: " + Environment.NewLine + strRequest);
StreamReader streamIn = new StreamReader(req.GetResponse().GetResponseStream());
strResponse = streamIn.ReadToEnd();
streamIn.Close();
现在，我想拥有一个接受POST方法的Web服务. 有谁知道如何做到这一点.我被困在这里.
Now i would like to have a webservice that accepts POST method. Does anyone has an idea how to do this. I'm stuck here.
推荐答案
可以在配置中启用HTTP GET和HTTP POST.根目录中存在一个名为webconfig文件的文件，您必须在其中添加以下设置:
HTTP GET and HTTP POST may be enabled in the configuration. There exists a file called webconfig file in the root where in you have to add the following setting:
<configuration>
<system.web>
<webServices>
<protocols>
<add name="HttpGet"/>
<add name="HttpPost"/>
</protocols>
</webServices>
</system.web>
</configuration>
即位于system.web标记内.
ie inside the system.web tag.
现在，如果您打算将XML发送回Web服务，则可以设计一个类似于预期XML的愿望结构. 例如:要获取以下类型的XML:
Now in the web-service if you are intending to send an XML back you could design a struct of your wish which resembles the anticipated XML. eg: To get an XML of following type:
<?xml version="1.0" encoding="utf-8"?>
<Quote xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="http://tempuri.org/">
<object>Item101</object>
<price>200</price>
</Quote>
您必须从Web服务返回以下结构的对象:
you have to return an object of following struct from the web-service:
public struct Quote
{
public int price;
public string object;
public Quote(int pr, string obj)
{
price = pr;
object = obj
}
}
现在，它可以作为字符串接收作为响应，然后根据需要进行解析.
Now this can be received as response as string and then be parsed as you like.
================================================ ===============================
===============================================================================
以下是HelloWorld WebMethod
The following is a HelloWorld WebMethod
[WebMethod]
public string HelloWorld() {
return "HelloWorld";
}
[如果将结构更改为返回类型，则返回相应的结构类型]
[in case of struct change the return type to corresponding struct type]
以下是一个函数，您可以在其中发布到URL，也可以将xml文件发送到Web服务[根据需要使用]:
The following is a function where you can POST to a URL and also send a xml file to the webservice[Use according to your need]:
public static XmlDocument PostXMLTransaction(string URL, XmlDocument XMLDoc)
{
//Declare XMLResponse document
XmlDocument XMLResponse = null;
//Declare an HTTP-specific implementation of the WebRequest class.
HttpWebRequest objHttpWebRequest;
//Declare an HTTP-specific implementation of the WebResponse class
HttpWebResponse objHttpWebResponse = null;
//Declare a generic view of a sequence of bytes
Stream objRequestStream = null;
Stream objResponseStream = null;
//Declare XMLReader
XmlTextReader objXMLReader;
//Creates an HttpWebRequest for the specified URL.
objHttpWebRequest = (HttpWebRequest)WebRequest.Create(URL);
try
{
//---------- Start HttpRequest
//Set HttpWebRequest properties
byte[] bytes;
bytes = System.Text.Encoding.ASCII.GetBytes(XMLDoc.InnerXml);
objHttpWebRequest.Method = "POST";
objHttpWebRequest.ContentLength = bytes.Length;
objHttpWebRequest.ContentType = "text/xml; encoding='utf-8'";
//Get Stream object
objRequestStream = objHttpWebRequest.GetRequestStream();
//Writes a sequence of bytes to the current stream
objRequestStream.Write(bytes, 0, bytes.Length);
//Close stream
objRequestStream.Close();
//---------- End HttpRequest
//Sends the HttpWebRequest, and waits for a response.
objHttpWebResponse = (HttpWebResponse)objHttpWebRequest.GetResponse();
//---------- Start HttpResponse
if (objHttpWebResponse.StatusCode == HttpStatusCode.OK)
{
//Get response stream
objResponseStream = objHttpWebResponse.GetResponseStream();
//Load response stream into XMLReader
objXMLReader = new XmlTextReader(objResponseStream);
//Declare XMLDocument
XmlDocument xmldoc = new XmlDocument();
xmldoc.Load(objXMLReader);
//Set XMLResponse object returned from XMLReader
XMLResponse = xmldoc;
//Close XMLReader
objXMLReader.Close();
}
//Close HttpWebResponse
objHttpWebResponse.Close();
}
catch (WebException we)
{
//TODO: Add custom exception handling
throw new Exception(we.Message);
}
catch (Exception ex)
{
throw new Exception(ex.Message);
}
finally
{
//Close connections
objRequestStream.Close();
objResponseStream.Close();
objHttpWebResponse.Close();
//Release objects
objXMLReader = null;
objRequestStream = null;
objResponseStream = null;
objHttpWebResponse = null;
objHttpWebRequest = null;
}
//Return
return XMLResponse;
}
呼叫将是:
XmlDocument XMLdoc = new XmlDocument();
XMLdoc.Load("<xml file locatopn>");
XmlDocument response = PostXMLTransaction("<The WebService URL>", XMLdoc);
string source = response.OuterXml;
[如果有帮助或需要更多帮助，请告诉我]
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