如何在链接中发送带有查询字符串的$ _POST [英] How Can I send $_POST with query string in a link
问题描述
这是php代码，用于检查是否发布了表单(在同一页面上)并根据$ _POST数组获取结果(如果已发布)或从数据库返回所有结果.这还会设置$ total变量，该变量包含稍后用于分页的number_of_pages
This is php code which checks if form(on same page) is posted and gets the result depending upon $_POST array if it is posted or returns all results from data base. this also sets $total variable containing number_of_pages later used for pagination
if(!isset($_POST['search']))
{
$id = (isset($_GET['id']) ? $_GET['id'].'0' : 10);
$id = $id-10;
$query = "select SQL_CALC_FOUND_ROWS * from feedbacks order by Date desc limit $id, 10 ";
}
else if (!empty($_POST['from']))
{
$timstmp = strtotime($_POST['from']);
$dt = date("Y-m-d H:i:s", $timstmp);
$id = (isset($_GET['id']) ? $_GET['id'].'0' : 10);
$id = $id-10;
$query = "SELECT SQL_CALC_FOUND_ROWS * FROM `feedbacks` WHERE `Date` >= \"$dt\" order by Date desc limit $id, 10 ";
}
else if (!empty($_POST['name']))
{
$name = '%'.$_POST['name'].'%';
$id = (isset($_GET['id']) ? $_GET['id'].'0' : 10);
$id = $id-10;
$query = "SELECT SQL_CALC_FOUND_ROWS * FROM `feedbacks` WHERE `name` LIKE '$name' order by Date desc limit $id, 10 ";
}
$result= mysqli_query($connection, $query);
$r = mysqli_fetch_array(mysqli_query($connection, 'SELECT FOUND_ROWS()'));
$total = ceil($r['FOUND_ROWS()']/10);
$feedbacks = array();
for ($i = 0;$row= mysqli_fetch_assoc($result); $i++)
{
$feedbacks[$i] = new FeedBack($row);
}
?>
这些是根据页面总数自动生成的html链接，而页面总数是根据数据库的结果而计算的
These are the html links that are automatically generated depending upon the total number of pages which is calculated depending upon results from data base
<?php
if ($total>1)
{ ?> <div class="pagging">
<?php for( $i=$total; $i>=1; $i--)
{ ?>
<div class="right">
<a id="pagination" href="index.php?id=<?php echo $i; ?>"><?php echo $i; ?></a>
</div>
<?php } ?>
</div>
<?php } ?>
</div>
<!-- Table -->
在此页面上，我正在实施过滤器.用户以表格形式输入数据并按搜索，以便根据$ _POST数组加载不同的结果，并修改包含num_of_pages的变量$ total，因为php代码的第一个块显示了第一页，现在第一页显示了使用偏移量的数据库的第1个10个结果0或ofset = IDX10-10(如果设置了id)，但问题是它仅适用于默认结果，即，当显示所有结果且未应用过滤器时，但当用户搜索经过过滤的第1个结果时，将显示10个过滤结果，但当用户单击下一页它不起作用，因为$ _POST未设置，已由php如果上述php代码中的条件进行了检查.所以我的问题是我该如何发送$ _POST []和ID来使其正常工作.任何帮助，将不胜感激.谢谢.
On this page I'm implementing filters. User input data in the form and press search so depending upon the $_POST array the different results are loaded and variable $total containing num_of_pages is modified as the 1st block of php code shows now the first page displays 1st 10 results from data base using offset 0 or ofset = IDX10-10 if id is set but problem is that it only works for default results i.e when all results are displayed and filter is not applied but when user searches through a filtered 1st 10 filtered results are displayed but when user clicks the next page it does not work because $_POST is unset which was checked by the php If conditions in above php code. so my question is how can i send $_POST[] along with the id to make it work. Any help would be appreciated. Thanks.
推荐答案
您无法通过链接发送POST变量.您需要使用GET.
You can't send POST variables through a link. You need to use GET.
<a href="some_page.php?<?=http_build_query($assc_array);?>">Link</a>
//the link will reflect some_page.php?name1=value1&name2=value2...etc
在PHP方面，请使用$ _GET或$ _REQUEST变量，而不是$ _POST.
On the PHP side use the $_GET or $_REQUEST variable, instead of $_POST.
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