PostgreSQL使用不同的ORDER BY打开 [英] PostgreSQL DISTINCT ON with different ORDER BY

问题描述

我要运行此查询:

SELECT DISTINCT ON (address_id) purchases.address_id, purchases.*
FROM purchases
WHERE purchases.product_id = 1
ORDER BY purchases.purchased_at DESC

但是我得到这个错误:

PG ::错误:错误:SELECT DISTINCT ON表达式必须与初始ORDER BY表达式匹配

PG::Error: ERROR: SELECT DISTINCT ON expressions must match initial ORDER BY expressions

将address_id添加为第一个ORDER BY表达式可以使错误静音，但是我真的不想添加对address_id的排序.是否可以不按address_id排序?

Adding address_id as first ORDER BY expression silences the error, but I really don't want to add sorting over address_id. Is it possible to do without ordering by address_id?

推荐答案

文档说:

DISTINCT ON(expression [，...])仅保留给定表达式求值相等的每组行的第一行. [...]注意，除非使用ORDER BY来确保所需的行首先出现，否则每个集合的第一行"都是不可预测的. [...] DISTINCT ON表达式必须与最左边的ORDER BY表达式匹配.

DISTINCT ON ( expression [, ...] ) keeps only the first row of each set of rows where the given expressions evaluate to equal. [...] Note that the "first row" of each set is unpredictable unless ORDER BY is used to ensure that the desired row appears first. [...] The DISTINCT ON expression(s) must match the leftmost ORDER BY expression(s).

官方文档

因此，您必须将address_id添加到订单依据.

So you'll have to add the address_id to the order by.

或者，如果您要查找包含每个address_id最近购买的产品并按purchased_at排序的结果的完整行，那么您正在尝试解决每个组中最大的N问题，这可能是通过以下方法解决:

Alternatively, if you're looking for the full row that contains the most recent purchased product for each address_id and that result sorted by purchased_at then you're trying to solve a greatest N per group problem which can be solved by the following approaches:

适用于大多数DBMS的一般解决方案:

The general solution that should work in most DBMSs:

SELECT t1.* FROM purchases t1
JOIN (
    SELECT address_id, max(purchased_at) max_purchased_at
    FROM purchases
    WHERE product_id = 1
    GROUP BY address_id
) t2
ON t1.address_id = t2.address_id AND t1.purchased_at = t2.max_purchased_at
ORDER BY t1.purchased_at DESC

基于@hkf的答案的更多面向PostgreSQL的解决方案:

A more PostgreSQL-oriented solution based on @hkf's answer:

SELECT * FROM (
  SELECT DISTINCT ON (address_id) *
  FROM purchases 
  WHERE product_id = 1
  ORDER BY address_id, purchased_at DESC
) t
ORDER BY purchased_at DESC

问题在这里得到澄清，扩展和解决:选择按某一列排序而又在另一列上不同的行

Problem clarified, extended and solved here: Selecting rows ordered by some column and distinct on another

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