SQL查询以获取主管层次结构列表。员工->主管->主管 [英] SQL query to get the list of supervisor hierarchy. employee --> supervisor --> supervisor

问题描述

我有两个表Employee和Department这幅图显示了每个员工的经理。我想编写一个SQL查询，为我提供所有主管（经理，经理的经理..）的列表。

I have two tables Employee and Department this image shows the manager of every employee. I want to write a SQL query that gives me a list of all the supervisor (Manager, Manager of Manager..).

我只希望显示一列授予特定雇员时的主管名单。

I just want a single column that displays a list of supervisor when given a particular employee.

例如如果我给员工id = 202，那么我应该收到200,130

E.g. If I give employee id = 202 then I should receive 200,130

 |supervisor |   
 +-----------+
 |   200     |      
 |   130     | 

我有此查询

WITH emp_dept as(
SELECT employee_id,manager_id 
FROM employee,department
WHERE employee.dept_id= department.dept_id
   ) 

 WITH recursive p as (
    select e1.employee_id, e1.manager_id
    from   emp_dept e1
    where    employee_id = 202

    union all

   select e2.employee_id , e2.manager_id
   from   p
   join   emp_dept e2 ON e2.employee_id = p.manager_id

)
select manager_id
from   p

`

能够使用它。我正在使用pgadmin4。

I am not able to use it. I am using pgadmin4.

如果有人可以帮助我进行此查询，我将不胜感激

If anyone could help me with this query I would greatly appreciate it

推荐答案

这是我问题的解决方案

  with recursive p as (
WITH emp_dept as(
SELECT employee_id,manager_id 
FROM employee,department
WHERE employee.dept_id= department.dept_id
) 

select e1.employee_id, e1.manager_id
from   emp_dept e1
where  e1.employee_id = 202

union 

select e2.employee_id , e2.manager_id
from   p
join   emp_dept e2 ON e2.employee_id = p.manager_id

)
select manager_id
  from   p

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