使用同一表中的值更新行 [英] UPDATE rows with values from the same table

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本文介绍了使用同一表中的值更新行的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个这样的表:

+------+-------+
|ID    | value |
+------+-------+
| 1    | 150   |
| 2    |       |
| 3    |       |
| 4    |       |
| 5    | 530   |
| 6    | 950   |
| 7    | 651   |
+-------+------+

I要复制最后3个值,最后我的表将如下所示:

I want to copy the last 3 values and at the end my table will look like this:

+------+-------+
|ID    | value |
+------+-------+
| 1    | 150   |
| 2    | 530   |
| 3    | 950   |
| 4    | 651   |
| 5    | 530   |
| 6    | 950   |
| 7    | 651   |
+-------+------+

推荐答案

使用自加入

UPDATE mytable m
SET    value = m0.value
FROM   mytable m0
WHERE  m.id = (m0.id - 3)   -- define offset
AND    m.id BETWEEN 2 AND 4 -- define range to be affected
AND    m.value IS NULL;     -- make sure only NULL values are updated

如果ID空间中存在间隙,请使用Windows函数 row_number()来获取完整的ID。我在CTE中这样做,因为我将重复使用该表两次以进行自联接:

If there are gaps in the ID space, use the windows function row_number() to get gapless ID to work with. I do that in a CTE, because I am going to reuse the table twice for a self-join:

WITH x AS (
   SELECT *, row_number() OVER (ORDER BY ID) AS rn
   FROM   mytable
   )
UPDATE mytable m
SET    value = y.value
FROM   x
JOIN   x AS y ON x.rn = (y.rn - 4567)   -- JOIN CTE x AS y with an offset
WHERE  x.id = m.id                      -- JOIN CTE x to original
AND    m.id BETWEEN 1235 AND 3455
AND    m.value IS NULL;

对于修改数据的CTE

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