SqlAlchemy(Postgres + Flask):如何求和多列? [英] SqlAlchemy (Postgres + Flask ) : How to sum multiple columns?
问题描述
我有一个类 Score
,其列为 item_id
,还有几个字段具有不同的分数类型(score1,score2, score3 ...)都具有整数值。
I have a class Score
with a column item_id
and several fields having different scores types(score1, score2, score3...)all having integer values.
我需要编写一个查询,该查询将获取分数类型列表并返回包含 itemid
以及列表中提到的所有分数类型的分数总和。我正在尝试使用混合方法执行此操作,但对如何编写查询感到困惑。
I need to write a query that takes the list of scores types and returns a list with objects having itemid
and sum of the scores of all score types mentioned in the list alongside. I'm trying to do this using hybrid method but confused about how to write the query.
model.py
class Score(db.Model):
__tablename__ = 'scores'
item_id = db.Column(db.Integer(), primary_key=True)
score1 = db.Column(db.Integer(), nullable=False)
score2 = db.Column(db.Integer(), nullable=False)
score3 = db.Column(db.Integer(), nullable=False)
score4 = db.Column(db.Integer(), nullable=False)
@hybrid_method
def total_score(self, fields):
ts = 0
for field in fields :
ts = ts + self[field]
return ts
controller.py
app.route('/scores', methods=['POST'])
def scores():
fields = ['score1', 'score2']
scores = Score.query.all().order_by('total_score')
显然不起作用。
这是我需要的最终输出:
This is how I need to have the final output :
[{'item_id' : 'x1', 'total_score' : y1},{'item_id' : 'x2', 'total_score' : y2},{'item_id' : 'x3', 'total_score' : y3}, ...]
推荐答案
您需要创建表达式,用于 hybrid_method
class Score(db.Model):
__tablename__ = 'scores'
item_id = db.Column(db.Integer(), primary_key=True)
score1 = db.Column(db.Integer(), nullable=False)
score2 = db.Column(db.Integer(), nullable=False)
score3 = db.Column(db.Integer(), nullable=False)
score4 = db.Column(db.Integer(), nullable=False)
@hybrid_method
def total_score(self, fields):
return sum(getattr(self, field) for field in fields)
@total_score.expression
def total_score(cls, fields):
return sum(getattr(cls, field) for field in fields)
fields = ['score1', 'score2']
scores = db.session.query(Score.item_id, Score.total_score(fields).label('total_score')).order_by('total_score')
final_output = [score._asdict() for score in scores]
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