删除=和？的最佳方法从PHP中的get方法？ [英] Best way to remove = and ? from get method in PHP?

问题描述

删除=和的最佳方法是什么？从PHP的get方法获取URL？我正在研究网站的分页结构，目前这是URL的样子：

What's the best way to remove the = and ? in a URL from the get method in PHP? I'm working on the pagination structure of my website and currently this is what the URLs look like:

www.example/test/?page=3

我希望它看起来像这样：

I want it to look like this:

www.example/test/3

是否可以使用一些额外的代码直接在PHP get方法中解决此问题，还是必须通过htaccess文件完成？

Can this be addressed directly in the PHP get method with some extra code or does it have to be done through an htaccess file?

这是我的htaccess文件现在的样子：

This is what my htaccess file looks like right now:

RewriteBase /  
RewriteEngine on
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteCond %{REQUEST_FILENAME}\.html -f
RewriteRule ^(.*)$ $1.html
RewriteCond %{REQUEST_URI} /index\.html?$ [NC]
RewriteRule ^(.*)index\.html?$ "/$1" [NC,R=301,NE,L]

推荐答案

这是我的尝试，我从涉及URL提取的不同StackOverflow主题中整理了一些已经存在的答案，然后提出了以下解决方案：

Here is my try, I compacted some already existing answer from different StackOverflow topics dealing with URL extraction and I came up with this solution :

<?php
    function http_protocol() {
        /**
         * @see https://stackoverflow.com/a/6768831/3753055
         */
        return (isset($_SERVER['HTTPS']) ? 'https' : 'http') . '://';
    }

    function http_host() {
        return $_SERVER['HTTP_HOST'];
    }

    function http_uri() {
        return parse_url($_SERVER["REQUEST_URI"], PHP_URL_PATH);
    }

    function http_refactored_query_strings() {
        $queries = explode('&', $_SERVER['QUERY_STRING']);
        $refactoredQueries = [];

        foreach( $queries as $query ) {
            $refactoredQueries[] = filter_var(explode('=', $query)[1], FILTER_SANITIZE_STRING);
        }

        $queries = implode('/', $refactoredQueries);

        return $queries ?: '';
    }

    function http_refactored_url() {
        return http_protocol() . http_host() . http_uri() . http_refactored_query_strings();
    }

    echo http_refactored_url();
?>

尝试使用一些示例：

• 获取 http://example.com/test.php ： http://example.com/test.php


• 获取 http://example.com/test.php?page=3 ： http://example.com/test.php/3


• 获取 https://example.com/test.php?view=page?page=3 ： https://example.com/page/3


• 获取 http://example.com/?page=3： http://example.com/3

• GET http://example.com/test.php : http://example.com/test.php
• GET http://example.com/test.php?page=3 : http://example.com/test.php/3
• GET https://example.com/test.php?view=page?page=3 : https://example.com/page/3
• GET http://example.com/?page=3 : http://example.com/3

对于查询字符串重构部分，我使用了 $ _ SERVER ['QUERY_STRING] 并将值分解为& 字符。因为第一个？不包含在 $ _ SERVER ['QUERY_STRING'] 中。因此，您想出了很多数组，其中包含 page = 3 ， view = page 等字符串，以及foreach，请使用 = 分隔符将其拆分，然后获取第二个元素（索引： 1 ）以将其附加到解决方案。

For the query string refactoring part, I used $_SERVER['QUERY_STRING] and exploded the value to & character. because the first ? is not contained in $_SERVER['QUERY_STRING']. So you come up with lot of arrays, containing strings like page=3, view=page, ... And foreach one, you split it using = delimiter and get the second element (index : 1) to append it to the solution.

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