在网址中显示ID号&将数据库结果从ID号获取到文本字段中 [英] Display ID Number in URL & fetch database results from ID Number into textfields
问题描述
我在一个网站上工作，我想在URL上显示ID号以及获取其属性（例如用户名，名字，姓氏）
I'm working on a website where I want to display the ID Number on the url as well as fetch its attributes along with it(e.g username, firstname, lastname)
例如，如果我输入： localhost / search / index3.php？u = 3 ，它将在页面上将数据库值显示在文本字段中。
An example would be if I type: localhost/search/index3.php?u=3, it would display the database values with it on the page into the textfields.
这是我的.htaccess的代码
Here's the codefor my .htaccess
RewriteEngine On
RewriteCond %{REQUEST_FILENAME} -f [OR]
RewriteCond %{REQUEST_FILENAME} -d
RewriteRule ^(.*)$ http://localhost/search/index3.php?u=$1 [NC]
这是我其余的代码
<?php
$host = "localhost";
$user = "root";
$password ="";
$database = "ntmadb";
$id = "";
$firstname = "";
$lastname = "";
$username = "";
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
// connect to mysql database
try{
$connect = mysqli_connect($host, $user, $password, $database);
} catch (mysqli_sql_exception $ex) {
echo 'Error';
}
// get values from the form
function getPosts()
{
$posts = array();
$posts[0] = $_POST['id'];
$posts[1] = $_POST['firstname'];
$posts[2] = $_POST['lastname'];
$posts[3] = $_POST['username'];
return $posts;
}
// Search
if(isset($_POST['search']))
{
$data = getPosts();
$search_Query = "SELECT * FROM members WHERE id = $data[0]";
$search_Result = mysqli_query($connect, $search_Query);
if($search_Result)
{
if(mysqli_num_rows($search_Result))
{
while($row = mysqli_fetch_array($search_Result))
{
$id = $row['id'];
$firstname = $row['firstname'];
$lastname = $row['lastname'];
$username = $row['username'];
}
}else{
echo 'No Data For This Id';
}
}else{
echo 'Result Error';
}
}
// Insert
if(isset($_POST['insert']))
{
$data = getPosts();
$insert_Query = "INSERT INTO `members`(`firstname`, `lastname`, `username`) VALUES ('$data[1]','$data[2]','$data[3]')";
try{
$insert_Result = mysqli_query($connect, $insert_Query);
if($insert_Result)
{
if(mysqli_affected_rows($connect) > 0)
{
echo 'Data Inserted';
}else{
echo 'Data Not Inserted';
}
}
} catch (Exception $ex) {
echo 'Error Insert '.$ex->getMessage();
}
}
// Delete
if(isset($_POST['delete']))
{
$data = getPosts();
$delete_Query = "DELETE FROM `members` WHERE `id` = $data[0]";
try{
$delete_Result = mysqli_query($connect, $delete_Query);
if($delete_Result)
{
if(mysqli_affected_rows($connect) > 0)
{
echo 'Data Deleted';
}else{
echo 'Data Not Deleted';
}
}
} catch (Exception $ex) {
echo 'Error Delete '.$ex->getMessage();
}
}
// Edit
if(isset($_POST['update']))
{
$data = getPosts();
$update_Query = "UPDATE `members` SET `firstname`='$data[1]',`lastname`='$data[2]',`username`='$data[3]' WHERE `id` = $data[0]";
try{
$update_Result = mysqli_query($connect, $update_Query);
if($update_Result)
{
if(mysqli_affected_rows($connect) > 0)
{
echo 'Data Updated';
}else{
echo 'Data Not Updated';
}
}
} catch (Exception $ex) {
echo 'Error Update '.$ex->getMessage();
}
}
?>
<!DOCTYPE Html>
<html>
<head>
<title>PHP INSERT UPDATE DELETE SEARCH</title>
</head>
<body>
<form action="indexx.php?id=" method="post">
<input type="number" name="id" placeholder="Id" value="<?php echo $id;?>"><br><br>
<input type="text" name="firstname" placeholder="First Name" value="<?php echo $firstname;?>"><br><br>
<input type="text" name="lastname" placeholder="Last Name" value="<?php echo $lastname;?>"><br><br>
<input type="text" name="username" placeholder="username" value="<?php echo $username;?>"><br><br>
<div>
<!-- Input For Add Values To Database-->
<input type="submit" name="insert" value="Add">
<!-- Input For Edit Values -->
<input type="submit" name="update" value="Update">
<!-- Input For Clear Values -->
<input type="submit" name="delete" value="Delete">
<!-- Input For Find Values With The given ID -->
<input type="submit" name="search" value="Find">
</div>
</form>
</body>
</html>
我希望有人这可以帮助我进行设置。
I hope anyone here can help me set it up. Thanks in advance!
推荐答案
您正在引用
if(isset($_POST['search']))
您需要查看 $ _ GET ['u'] 以获得传入的ID。
You need to be looking at $_GET['u'] to get the id passed in.
Relevant pages in the manual: $_POST , $_GET
编辑：仅阅读代码，还有其他一些错误，例如以下几位来自用户发布表单的示例。 （即 getPost（）位）。如果您尝试基于传入的ID从数据库中获取详细信息，则不需要。
just reading through the code, there are a few other bits wrong as the following bits are from an example where a user has posted a form. (ie. the getPost() bit). You don't need that if you're trying to get details from a database based on a passed in ID.
if (isset($_GET['u'])) {
if ($stmt = $mysqli->prepare("SELECT * FROM members WHERE id = ?")) {
/* bind parameters for markers */
$stmt->bind_param("i", $_GET['u']);
/* execute query */
$stmt->execute();
if ($stmt->affected_rows) {
// Deleted
} else {
// Not found / deleted
}
}
}
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