使用ConditionalAttribute是否还会删除参数计算？ [英] Does using ConditionalAttribute also remove arguments computation?

问题描述

我尝试了以下代码：

class Magic {
   [Conditional("DEBUG")]
   public static void DoMagic( int stuff )
   {
   }
   public static int ComputeMagic()
   {
      throw new InvalidOperationException();
   }
}
class Program
{
   static void Main(string[] args)
   {
      Magic.DoMagic(Magic.ComputeMagic());
   }
}

看起来在Release build中不是这样抛出的结果不仅删除了对标记为 ConditionalAttribute 的方法的调用，而且消除了参数计算。

and it looks like in Release build the exception is not thrown so not only the call to a method marked with ConditionalAttribute is removed, but also the parameters computation is eliminated.

这样的行为是否得到保证？

Is such behavior guaranteed?

推荐答案

是的，当 DEBUG 未定义（这在发行版中很常见）。

Yes, argument evaluation is removed when DEBUG is not defined (which is typical in Release builds).

来自 http://msdn.microsoft.com/zh-cn/library/aa664622%28v=vs.71%29.aspx ：

如果定义了符号，则包括该调用；否则，将忽略呼叫
（包括对呼叫参数的评估）。

If the symbol is defined, the call is included; otherwise, the call (including evaluation of the parameters of the call) is omitted.

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