c＃float []平均值失去准确性 [英] c# float [] average loses accuracy

问题描述

我正在尝试计算浮点数组的平均值。我需要使用索引，因为它在二进制搜索中，因此顶部和底部将移动。 （大图，我们正在尝试优化半范围估计，因此我们不必在每次通过时都重新创建数组。）

I am trying to calculate average for an array of floats. I need to use indices because this is inside a binary search so the top and bottom will move. (Big picture we are trying to optimize a half range estimation so we don't have to re-create the array each pass).

无论如何，我写了一个自定义的平均循环而且我得到的精度比c＃Average（）方法低2位。

Anyway I wrote a custom average loop and I'm getting 2 places less accuracy than the c# Average() method

float test = input.Average();

int count = (top - bottom) + 1;//number of elements in this iteration
int pos = bottom;
float average = 0f;//working average
while (pos <= top)
{
     average += input[pos];
     pos++;
}
average = average / count;

示例：

0.0371166766 - c#
0.03711666 - my loop

125090.148 - c#
125090.281 - my loop 

http://pastebin.com/qRE3VrCt

推荐答案

我得到的精度比c＃Average（）低2位

I'm getting 2 places less accuracy than the c# Average()

否，您仅损失1个有效数字。浮动类型只能存储7个有效数字，其余的只是随机噪声。不可避免地，在这样的计算中，您会累积舍入误差，从而失去精度。

No, you are only losing 1 significant digit. The float type can only store 7 significant digits, the rest are just random noise. Inevitably in a calculation like this, you can accumulate round-off error and thus lose precision. Getting the round-off errors to balance out requires luck.

唯一避免这种情况的方法是使用浮点类型，该浮点类型具有更高的精度来累加结果。没问题，您可以使用 double 。这就是为什么Linq Average方法看起来像这样的原因：

The only way to avoid it is to use a floating point type that has more precision to accumulate the result. Not an issue, you have double available. Which is why the Linq Average method looks like this:

   public static float Average(this IEnumerable<float> source) {
       if (source == null) throw Error.ArgumentNull("source");
       double sum = 0;         // <=== NOTE: double
       long count = 0;
       checked {
           foreach (float v in source) {
               sum += v;
               count++;
           }
       }
       if (count > 0) return (float)(sum / count);
       throw Error.NoElements();
   }

使用 double 重现Linq结果结果中可比较的有效数字位数。

Use double to reproduce the Linq result with a comparable number of significant digits in the result.

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