创建多个.xaml视图 [英] Creating multiple .xaml Views

问题描述

我想创建一个名为 view.xaml 的.xaml UserControl的多个实例，该实例位于程序集 dir1\asm.dll 和 dir2\asm.dll ，而 asm.dll 是同一程序集，只是不同在版本号和view.xaml的实现中。

我有以下设置：

  public void TestCreation（）{
 
汇编asm = null; 
 
 asm = Assembly.LoadFile（ dir1\asm.dll）; 
 CreateView（asm）; //有效！ 
 
 asm = Assembly.LoadFile（ dir2\asm.dll）; 
 CreateView（asm）; //有效！ 
 
 asm = Assembly.LoadFile（ dir1\asm.dll）; 
 CreateView（asm）; //失败！ 
 
} 
 
 public void CreateView（Assembly assembly）
 {
 Type type = assembly.GetTypes（）。First< Type>（t => ; t.Name.Equals（ View））; 
 
 UserControl视图=（UserControl）assembly.CreateInstance（type.FullName，false，BindingFlags.CreateInstance，null，新对象[] {}，null，null）; 
} 
  

我收到以下异常：

带有异常详细信息

我能够在我视图的InitializeComponent（）方法中一直跟踪到该位置的问题。 xaml：

，尤其是在InitializeComponent（ ）：

解决方案

在经历了一周的苦苦挣扎之后，我终于找到了两个原因问题和解决方案。

问题出在自动生成的 *。gics 文件中由 UserControl 的 InitializeComponent（）方法调用，如下所示：

此文件生成表示路径的字符串（资源定位器）如下所示：

现在，如果您拥有同一程序集的多个版本，并且两个版本包含相同的xaml文件， WPF 不知道要实例化哪个xaml文件，因为资源定位器仅引用程序集的名称，而不引用程序集的版本。

这将导致 TargetInvocationException ，表示

{组件'MyNamespace.MyUserControl'没有由URI'/MyAssembly;comoponent/myusercontrol.xaml'标识的资源}

如下：

此商品的赠送金额为：

• 此博客


• 此SO线程

I want to create multiple instances of a .xaml UserControl named view.xaml, which resides in an assembly dir1\asm.dll and dir2\asm.dll whereas asm.dll is the same assembly that only differs in its version number and the implementation of view.xaml.

I have the following setup:

public void TestCreation() {

    Assembly asm = null;

    asm = Assembly.LoadFile("dir1\asm.dll");
    CreateView(asm); // works!

    asm = Assembly.LoadFile("dir2\asm.dll");
    CreateView(asm); // works!

    asm = Assembly.LoadFile("dir1\asm.dll");
    CreateView(asm); // FAILS!

}

public void CreateView(Assembly assembly)
    {
        Type type = assembly.GetTypes().First<Type>(t => t.Name.Equals("View"));

        UserControl view = (UserControl)assembly.CreateInstance(type.FullName, false, BindingFlags.CreateInstance, null, new object[] { }, null, null);
    }

I am getting the following Exception:

with the Exception detail

I was able to track the problem up to this location in the InitializeComponent() method of my view.xaml:

and more specificially within InitializeComponent():

解决方案

After a week suffering and laboring with this issue, I finally found both the reason for the problem and its solution.

The problem lies within the auto-generated *.g.i.cs file, which is called by the InitializeComponent() method of a UserControl, as seen by the following:

This file generates a string (a Resource Locator) that expresses the path to that xaml-component, as seen by the following:

Now, if you have multiple versions of the same assembly and both versions include the same xaml-file, WPF does not know what xaml-file to instantiate, because the Resource Locator only references the name of the assembly but not its version.

This results in a TargetInvocationException, saying that

{"The component 'MyNamespace.MyUserControl' does not have a resource identified by the URI '/MyAssembly;comoponent/myusercontrol.xaml'"}

as follows:

The simple (but most definitely not obvious) solution for this is to add the version of the assembly to this Resource Locator. This can be achieved by modifying the build-file of the project by adding the <AssemblyVersion>-tag as follows:

Credits for this go to:

• this blog
• this SO thread

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