如何以编程方式检测64位或32位计算机？ [英] How to programatically detect a 64 bit or 32 bit machine?

问题描述

我不明白32位和64位的含义。人们似乎说64位计算机的运行速度更快-但是为什么呢？这是否意味着有64位整数而不是32位？如果是这样，是否可以编写一种程序来确定我们是在32位还是64位计算机上？

I don't understand what 32 bit and 64 bit means. It seems that people say 64 bit computers run faster - but why? Does it mean that there are 64 bit integers instead of 32? If it's something like that, is there a way to write a program to determine if we're on a 32 bit or 64 bit machine?

推荐答案

在64位计算机上，指针为8字节（64位）。在32位计算机上，它们是4字节（32位）。因此，我们可以通过指针的大小来确定要处理的内容，形式最简单：

On 64-bit machines pointers are 8 bytes (64 bits). On 32-bit machines they are 4 bytes (32 bits). Thus we can determine by the size of a pointer what we are dealing with, in it's simplest form:

#define IS_64BIT (sizeof(void *) == 8)

唯一的缺点是64位计算机以32位运行模式将注册为32位。当然，这实际上并不重要，因为就所有意图而言，一台64位计算机上的32位操作系统将是一台32位计算机。

The only drawback is that a 64 bit computer running in 32 bit mode will register as 32 bit. Of course, this isn't actually important as for all intents and purposes a 32 bit OS on a 64 bit computer will be a 32 bit computer.

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