为什么Iterable接口中的forEach方法不是抽象的？ [英] Why the forEach method in Iterable interface is not abstract?

问题描述

当我看到Iterable接口源时，似乎 foreach 方法和 Spliterator 方法不是抽象的。接口如何具有非抽象方法？还是我有什么想念的？请参见下面的 Iterbale 接口源。

When I see the Iterable interface source, it looks like the foreach method and Spliterator methods are not abstract. How an interface can have non abstract methods? Or is there anything I am missing in this? See the Iterbale interface source below.

package java.lang;

import java.util.Iterator;
import java.util.Objects;
import java.util.Spliterator;
import java.util.Spliterators;
import java.util.function.Consumer;

public abstract interface Iterable<T>
{
  public abstract Iterator<T> iterator();

  public void forEach(Consumer<? super T> paramConsumer)
  {
    Objects.requireNonNull(paramConsumer);
    Iterator localIterator = iterator();
    while (localIterator.hasNext())
    {
      Object localObject = localIterator.next();
      paramConsumer.accept(localObject);
    }
  }

  public Spliterator<T> spliterator()
  {
    return Spliterators.spliteratorUnknownSize(iterator(), 0);
  }
}
/* Location:           C:\Program Files\Java\jre1.8.0_121\lib\rt.jar
 * Qualified Name:     java.lang.Iterable
 * Java Class Version: 8 (52.0)
 * JD-Core Version:    0.7.1
 */

推荐答案

使用Java 8，您可以定义接口的默认实现。

java.lang.Iterable 的作用是：

With Java 8 you can define a default implementation in the interface.
It is what java.lang.Iterable does :

public interface Iterable<T> {
    ...    
    default void forEach(Consumer<? super T> action) {
        Objects.requireNonNull(action);
        for (T t : this) {
            action.accept(t);
        }
    }
   ...
}

您的实际代码未引用Java 8源代码。

Your actual code doesn't refer the Java 8 source code.

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