Python：获取导入函数的抽象语法树？ [英] python: get the abstract syntax tree of imported function?

问题描述

假设我已经在解释器中导入了python模块。如何在解释器中获取导入模块（及其中的任何函数和类）的抽象语法树？我不想重新解析源文件。谢谢！

Let's say I've already imported a python module in the interpreter. How can I get the abstract syntax tree of the imported module (and any functions and classes within it) within the interpreter? I don't want to have to re-parse the source files. Thanks!

推荐答案

也许您会在此食谱中找到一些启发：

Maybe you find some inspiration in this recipe:

• http://code.activestate.com/ recipes / 533146-ast-pretty-printer /

• http://code.activestate.com/recipes/533146-ast-pretty-printer/

输出人类的函数可读版本的Python AST。

A function that outputs a human-readable version of a Python AST.

或使用编译器与检查（当然，仍使用源代码）：

Or use compiler combined with inspect (which, of course, still uses the source):

>>> import compiler, inspect
>>> import re # for testing 
>>> compiler.parse(inspect.getsource(re))
Module('Support for regular expressions (RE). \n\nThis module provides ...

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