是否可以在Android中使用Actionbar Sherlock在Action菜单项中实现切换按钮 [英] Is it possible to Implement Toggle Button in Action Menu Item using Actionbar sherlock in android

问题描述

我有一个应用，该应用的动作菜单项中有切换按钮，尽管我使用的是Actionbar Sherlock，但我不知道如何将切换按钮置于动作菜单项中。我不想作为自定义布局放置在操作栏中，但是我想将其作为菜单项放置。如果有人找到解决方案，请帮助我。

I have an app, which have toggle button in action menu item, though i'm using Actionbar Sherlock, I don't know, how to place the toggle button in the action menu item. I don't want to place as a custom layout in action bar, but i want to place it as a Menu item. If anyone find solution, Please help me out.

目的是，如果我更改切换按钮的状态，它将根据字母顺序对该人进行排序，并再次在出生日期中对其进行排序。

Purpose, If I change the state of toggle button, it will sort the person based on ALphabets and again in Date of Birth.

预先感谢！

推荐答案

就像普通的菜单按钮一样添加它，并用布尔值检查它的状态变量，则可以在更改排序方式时更改图标和标题

Just add it like a normal Menu Button, check its state with a boolean variable, and you can change the icon and title when changing the sortmode

boolean birthSort=false;
@Override
public boolean onOptionsItemSelected(MenuItem item) {
    switch (item.getItemId()) {
    case R.id.menu_toggle:

        if(birthSort){
            //change your view and sort it by Alphabet
            item.setIcon(icon1)
            item.setTitle(title1)
            birthSort=false;
        }else{
            //change your view and sort it by Date of Birth
            item.setIcon(icon2)
            item.setTitle(title2)
            birthSort=true;
        }
        return true;



    }
    return super.onOptionsItemSelected(item);


}

别忘了添加xml，就像其他任何菜单按钮一样，如果要在溢出中或外部显示它，请配置 android：showAsAction 。

Don't forget to add it in xml like any other menu button and configure android:showAsAction if you want to show it in overflow or outside of it.

<menu xmlns:android="http://schemas.android.com/apk/res/android">

<item android:id="@+id/menu_toogle"
    android:showAsAction="ifRoom"
    android:title="Share"
     />
</menu>

这篇关于是否可以在Android中使用Actionbar Sherlock在Action菜单项中实现切换按钮的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！