ActiveMQ删除特定消息 [英] ActiveMQ delete specific message

问题描述

我使用以下代码接收未删除的邮件。现在，我需要添加一些过滤条件并删除一些消息。我的问题是当其他邮件应留在队列中时如何删除特定邮件？

I use the following code to recieve messages without deletion. Now I need to add some filtering and delete some of the messages. My question is how to delete a specific message while other messages should stay in the queue?

    Uri connecturi = new Uri("activemq:tcp://model.net:61616");
    IConnectionFactory factory = new NMSConnectionFactory(connecturi);
    List<ModelBuilderBase> result = new List<ModelBuilderBase>();
    using (IConnection connection = factory.CreateConnection())
    using (ISession session = connection.CreateSession())
    {

        IDestination destination = SessionUtil.GetDestination(session, "queue://cidModelbuilderQ");
        using (IMessageConsumer consumer = session.CreateConsumer(destination))
        {
            connection.Start();
            var q = session.GetQueue("cidModelbuilderQ");
            var b = session.CreateBrowser(q);
            var msgs = b.GetEnumerator();
            while (msgs.MoveNext())
            {
                ITextMessage message = msgs.Current as ITextMessage;
                if (message.Properties[MANDATOR] == null || message.Properties[REFCODE] == null)
                    continue;
                var mandator = message.Properties[MANDATOR].ToString();
                var refCode = message.Properties[REFCODE].ToString();
                result.Add(ModelBuilderFactory.Instance.GetInstance(refCode, mandator));
            }
        }
    }

推荐答案

使用选择器并获取这些消息。

Use selectors and get these messages.

创建使用者时，由
创建。IMessageConsumer Consumer = session.CreateConsumer（destination， REFCODE> 200）
或类似内容，取决于您要查找的内容。
然后只需调用Consumer.receive（timeout_val）;直到拉出队列中所有选定的消息。
有关AMQ选择器的信息

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