ActiveRecord-从每个组中选择第一条记录 [英] ActiveRecord - select first record from each group

问题描述

我希望每个用户发送最新消息。这是示例数据

I want most recent message sent by each users. Here is sample data

表：对话

sender  receiver message                        date
============================================================
    1   2   "hi"                            "2013-03-04 09:55:01.122074"
    2   1   "hello"                         "2013-03-04 09:55:32.903975"
    1   2   "have you done with the taks?"  "2013-03-04 09:57:46.383007"
    2   1   "almost..."                     "2013-03-04 09:58:55.783219"
    2   1   "should be able to finish 2day" "2013-03-04 09:59:28.950705"
    2   3   "shall we start?"               "2013-03-04 10:01:16.842725"
    3   2   "give me a minute"              "2013-03-04 10:01:41.994589"
    3   2   "let us start"                  "2013-03-04 10:02:14.04551"

对于ID为2的用户，我应该能够得到以下两个记录

Where for user with id 2, I should be able to get following two record

1   2   "have you done with the taks?"  "2013-03-04 09:57:46.383007"        
3   2   "let us start"                  "2013-03-04 10:02:14.04551"

这是我的解决方案

型号：用户

class User < ActiveRecord::Base
has_many :chats_received, class_name: 'Conversation', foreign_key: 'receiver_id',order: "created_at DESC"
end

模型：对话

class Conversation < ActiveRecord::Base
  attr_accessible :message, :read

  belongs_to :sender, class_name: 'User'
  belongs_to :receiver, class_name: 'User'

  def most_recent_chat_received_from_connected_users
    connected_users_chats = . . . # Get all conversations which are sent to current user. e.g., user with id 2
    chats_grouped_by_senders = connected_users_chats.group_by { |conversation| conversation.sender_id }
    chats_grouped_by_senders.inject([]){|memo , (sender_id, conversations)| memo << conversations.first; memo}
  end
end

从连接中获取最新消息用户：

user = User.find 2
user.most_recent_chat_received_from_connected_users

尽管此解决方案有效，但它会为两个用户之间的每次转换选择并创建模型。我也觉得这不是获取必需行的方法。

Though this solution works, it select and create models for each conversion between two user. Also I feel it is not rails way of getting required rows.

我一直在使用postgresql。尝试在该模式下使用组方法时，出现以下错误。

I have been using postgresql. I have been getting following error when I try to use group method on the mode.

ActiveRecord::StatementInvalid: PG::Error: ERROR:  column "conversations.id" must appear in the GROUP BY clause or be used in an aggregate function

是否有更好的方法来获得相同的结果？

Is there any better way to get the same results?

推荐答案

我不确定如何调用 most_recent_chat_received_from_connected_users ，它是 Conversation 类的实例方法，位于 User 不会出错，但是我会向会话模型添加自定义查找器：

I'm not sure how you can call most_recent_chat_received_from_connected_users, which is an instance method of your Conversation class, on an instance of User without getting an error, but i would add a custom finder to the Conversation model:

class Conversation < ActiveRecord::Base
  # ...

  def self.most_recent_for(user_id)
    select('DISTINCT ON (sender_id) *').where(reciever_id: user_id).order("sender_id, created_at DESC")
  end

  # For MySQL you could have used:
  #
  # def self.most_recent_for(user_id)
  #   where(reciever_id: user_id).group("sender_id").order("created_at DESC")
  # end

  # ...
end

现在，您可以在控制器中通过以下方式获得所需的对话：

Now you can get the desired conversations in your controller with:

@conversations = Conversation.most_recent_for(current_user.id)

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