__add__支持不同类型的加法吗？ [英] __add__ to support addition of different types?

问题描述

如果python是支持重载的静态编程语言，它将非常容易解决。我正在制作一个名为Complex的类，它表示复数（我知道python有它自己的一类，但我想自己做一个），其中a是实数，b是虚数（ Complex （a，b））。它应该支持将Complex实例加在一起（ Complex（2，4）+ Complex（4，5）= Complex（6，9）），以及添加一个整数（ Complex（2，3）+ 4 =复杂（6，3））。但是，由于python的性质，因此...

Would be very easy to solve had python been a static programming language that supported overloading. I am making a class called Complex which is a representation of complex numbers (I know python has its own, but i want to make one myself), where a is the real number and b is the imaginary (Complex(a, b)). It should support adding Complex instances together (Complex(2, 4) + Complex(4, 5) = Complex(6, 9)), as well as adding an integer (Complex(2, 3) + 4 = Complex(6, 3)). However, due to the nature of python...

__add__(self, other):

...我必须选择要支持的类，因为它无法识别编译类型时间，以及不支持功能重载。最好的解决方案是什么？我是否必须编写与 other 参数的数据类型有关的if语句？

...I have to choose which the class will support, because it won't recognize types at compile-time, as well as not supporting overloading of functions. What is the best solution? Do I have to write an if statement in relation to the datatype of the other parameter?

推荐答案

您可以做的是检查实例Complex的内容，如果没有，则将其变成一个实例，就像这样：

What you could do is check for the thing being of instance Complex, and if not, turn it into one, like so:

def __add__(self, other):
    if isinstance(other, Complex):
        # do addition
    else:
        return self + Complex(other, 0)

这当然不会消除类型检查，但是会重用您在<$中所做的一切c $ c> __ init __ （可能正在检查输入是int还是float）。

That of course does not eliminate type checking, but it reuses whatever you are doing in __init__ (which is probably checking if input is int or float).

如果您目前不进行类型检查，在初始化中，这可能是个好主意，并且这看起来很合理，除了内置的复杂类型。

If at the moment you do not do type checking in init, it is probably a good idea, and this looks reasonable, excepting built-in complex type.

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