无法将the_field（）的值分配给变量 [英] Can't assign the value of the_field() to a variable

问题描述

我在Wordpress中使用高级自定义字段。我在字段中有一个文件路径（在字段 ACFfield中说 submenu / abc.php）。我想在网页上包含该信息。

I'm using Advanced Custom Fields in Wordpress. I have a file path in a field (say "submenu/abc.php" in field "ACFfield"). I want to include that info on a webpage.

如果我这样做：

<?php include "submenu/abc.php" ?>

这很好。但我需要做类似的事情：

This works fine. But I need to do something like:

<?php 

    $file = the_field(ACFfield);
    include($file);

?>

但这只是从第一行打印出 submenu / abc.php

This, however just prints out "submenu/abc.php", from the first line (which I wouldn't want visible anyway).

我在做什么错了？

推荐答案

the_field（ACFfield）; 不返回任何内容。它只是打印出文件名。改用 get_field（） 将返回值。

the_field(ACFfield); doesn't return anything. It just prints the filename out. Use get_field() instead, which will return the value.

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