R-为输出数据指定所需的行顺序。 [英] R - Specifying a desired row order for the output data.frame of aggregate()

问题描述

我 aggregate（）每个站点的值列总和 R data.frame的级别如下：

I aggregate() the value column sums per site levels of the R data.frame given below:

set.seed(2013)
df <- data.frame(site = sample(c("A","B","C"), 10, replace = TRUE),
                 currency = sample(c("USD", "EUR", "GBP", "CNY", "CHF"),10, replace=TRUE, prob=c(10,6,5,6,0.5)),
                 value = sample(seq(1:10)/10,10,replace=FALSE))

df.site.sums <- aggregate(value ~ site, data=df, FUN=sum)
df.site.sums

#  site value
#1    A   0.2
#2    B   0.6
#3    C   4.7

但是，我希望能够指定生成的 df.site.sums 的行顺序。例如：

However, I would like to be able to specify the row order of the resulting df.site.sums. For instance like:

reorder <- c("C","B","A")
?special_sort(df, BY=site, ORDER=reorder) # imaginary function
#  site value
#1    C   4.7
#2    B   0.6
#3    A   0.2

如何使用基数R做到这一点？需要明确的是，这本质上是数据框行排序问题，其中上下文是 aggregate（）函数（可能无关紧要）。

How can I do this using base R? Just to be clear, this is essentially a data frame row ordering question where the context is the aggregate() function (which may or may not matter).

这是相关的，但是不能直接解决我的问题，或者我错过了解决方案的症结所在。

This is relevant but does not directly address my issue, or I am missing the crux of the solution.

更新

为了将来参考，我找到了一种解决方案，可以根据目标向量对data.frame的行进行排序在此链接。我猜它可以用作后期处理步骤。

For future reference, I found a solution to ordering a data.frame's rows with respect to a target vector on this link. I guess it can be applied as a post-processing step.

df.site.sums[match(reorder,df.site.sums$site),]

推荐答案

这可能是可能性：将站点转换为因子并以级别指定顺序。

This may be a possibility: convert 'site' to a factor and specify the order in levels.

df$site2 <- factor(df$site, levels = c("C", "B", "A"))
aggregate(value ~ site2, data = df, FUN = sum)

#   site2 value
# 1     C   4.7
# 2     B   0.6
# 3     A   0.2

更新（谢谢！）。您可以使用汇总的非公式方法：

Update following @Ananda Mahto's comment (thanks!). You can use the 'non-formula' approach of aggregate:

reorder <- c("C", "B", "A")
with(df, aggregate(x = list(value = value),
                   by = list(site = factor(site, levels = reorder)),
                   FUN = sum))
#   site value
# 1    C   4.7
# 2    B   0.6
# 3    A   0.2

或者，在公式界面中转换为因数，然后重命名转换后的站点列：

Or, converting to factor within the formula interface, and rename the converted site column:

df2 <- aggregate(value ~ factor(site, levels = c("C", "B", "A")),
                 data = df, FUN = sum)
df2
names(df2) <- c("site", "value")
df2

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