Elasticsearch聚合排名(按热门得分) [英] Elasticsearch aggregation order by top hit score
本文介绍了Elasticsearch聚合排名(按热门得分)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想按top_hit的doc.score订购存储桶。我当前的实现如下。
I want to order buckets by doc.score of top_hit. My current implementation is below.
group_by_iid: {
terms: {
field: 'iid',
order: { max_score: 'desc' },
size: 0
},
aggs: {
max_score: { max: { script: 'doc.score' } },
top_hit: {
top_hits: {
sort: [{ source_priority: { order: 'desc' } }],
size: 1
}
}
}
}
这是错误的,因为存储桶按其最高得分排序,不是他们在source_priority文档中得分最高的分数。有解决这个问题的方法吗?
This is wrong because buckets are ordered by their top score, not their top source_priority document's score. Is there a way to solve this problem?
推荐答案
我遇到了同样的问题,而解决问题的方法是引入一个docs分数上的子汇总。然后在我的外部聚合中,我按max_score聚合的名称排序。
I had the same issue, and the way I resolved it was to introduce a sub-aggregation on the docs score. Then in my outer aggregation, I ordered by name of the max_score aggregation.
GET /my-index/my-type/_search
{
"query": {
"bool" : {
"should" : [ {
"match" : {
"searchTerm" : {
"query" : "style",
"type" : "boolean"
}
}
},
{
"flt_field" : {
"searchTerm" : {
"like_text" : "style"
}
}
}]
}
},
"aggs": {
"group_by_target_url": {
"terms": {
"field": "targetUrl",
"order": {
"max_score": "desc"
}
},
"aggs": {
"max_score": {
"max": {
"script": "doc.score"
}
}
}
}
}
}
我按照此链接:
这篇关于Elasticsearch聚合排名(按热门得分)的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文