如何解析喷雾路由中的获取请求参数？ [英] How can I parse out get request parameters in spray-routing?

问题描述

这是代码段的样子

    get{
      respondWithMediaType(MediaTypes.`application/json`){
          entity(as[HttpRequest]){
            obj => complete{


                println(obj)
                "ok"
            }
          }
      }
    }~

我可以将请求映射到spray.http.HttpRequest对象，并且可以从该对象中提取uri，但我想与手动执行操作相比，解析请求中的参数要容易得多。

I can map the request to a spray.http.HttpRequest object and I can extract the uri from this object but I imagine there is an easier way to parse out the parameters in a get request than doing it manually.

例如，如果我的get请求为

For example if my get request is

 http://localhost:8080/url?id=23434&age=24

我希望能够从此请求中获取ID和年龄

I want to be able to get id and age out of this request

推荐答案

实际上，您可以做得更好。在路由中有两个指令： parameter 和 parameters ，我想区别很明显，您也可以使用一些修饰符：！和？。如果是！，则意味着必须提供此参数，否则将拒绝请求，并返回？选项，因此您可以在这种情况下提供默认参数。示例：

Actually you can do this much much better. In routing there are two directives: parameter and parameters, I guess the difference is clear, you can also use some modifiers: ! and ?. In case of !, it means that this parameter must be provided or the request is going to be rejected and ? returns an option, so you can provide a default parameter in this case. Example:

val route: Route = {
  (path("search") & get) {
    parameter("q"!) { query =>
      ....
    }
  }
}

val route: Route = {
  (path("search") & get) {
    parameters("q"!, "filter" ? "all") { (query, filter) => 
      ...
    }
  }
}

这篇关于如何解析喷雾路由中的获取请求参数？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！