NSInvalidArgumentException JSON中的无效类型写入DemographicsPojo [英] NSInvalidArgumentException Invalid type in JSON write DemographicsPojo

问题描述

当我尝试使用 Alamofire JSONSerialization 时，我得到了 NSInvalidArgumentException >在 swift 3 代码上。

I am getting a NSInvalidArgumentException when I try to run the following JSONSerialization using Alamofire on swift 3 code.

尝试！ JSONSerialization.data（withJSONObject：postData，选项：JSONSerialization.WritingOptions.prettyPrinted）

try! JSONSerialization.data(withJSONObject: postData, options: JSONSerialization.WritingOptions.prettyPrinted)

在调试时， postData 返回下面的值。

On debug, postData is returning the value below.

key __NSCFString *  "demographicsPojo"  0x000060800005e8a0
value   _TtC7MyApp16DemographicsPojo *  0x6080001c5cd0  0x00006080001c5cd0
[0] _TtC7MyApp16DemographicsPojo    
createdTimeMilliSecs    Int64?  1487253369999
dateOfBirthMilliSecs    Int64?  1487253369999
demographicsRoleType    Int?    3
gender  Int?    0
isDemographicsActive    Int?    3
isRecordActive  Int?    0
isTermsAndConditionsAccepted    Int?    3
licenseExpiryDate   Int64?  1487253369999
mobilePhone String? "9876543210"    some
termsAndConditionsAcceptedTime  Int64?  1487253369999
termsAndConditionsText  String? ""  some
updatedTimeMilliSecs    Int64?  1487253369999

我是 Swift 3 的新手。我使用基于Android的JSON文件对 DemographicsPojo 进行反向工程以快速进行。我想知道是否需要避免在Pojo's中完全使用 Optionals ？这是问题吗？

I am new to Swift 3. I used my Android based JSON files to reverse engineer the DemographicsPojo to swift. I wonder if I need to avoid using Optionals completely in the Pojo's ? Is that the issue ?

推荐答案

Swift不会将任意对象序列化为JSON字符串。您可以通过调用 JSONSerialization.isValidJSONObject 进行检查。

Swift would not serialize arbitrary object into JSON string. You can check this with a call to JSONSerialization.isValidJSONObject.

您需要先将对象转换成字典。或使用第三方JSON序列化程序库，例如光泽

You need to convert your object into a dictionary first. Or use third-party JSON serializer library, like Gloss

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