如何一次又一次调用同一警报对话框？ [英] How to call same alert Dialog again and again?

问题描述

我创建了一个警报对话框，其中有两个 EditText 和两个 Button ，然后获取 EditText 的值，如果值匹配，那么我正在执行一些操作，否则我想调用相同的 AlertDialog 。如果值不同，则无法调用相同的警报对话框。我不知道我在哪里做错了...

I have create one Alert Dialog which have two EditText and two Button and I fetch the value of the EditText and if value matches then I am doing some operation otherwise I want to call same AlertDialog again.But if value differs then I am not able to call the same alert dialog.I don't know where i am doing wrong...

我的代码就像这样::

My Code goes like this ::

public class MainActivity extends Activity 
{
private Button btn_click;
@Override
public void onCreate(Bundle savedInstanceState) 
{
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    btn_click=(Button)findViewById(R.id.btn_click);
    btn_click.setOnClickListener(new OnClickListener()
    {
        @Override
        public void onClick(View arg0) 
        {
            showDialog(0);
        }
    });
}

@Override
protected Dialog onCreateDialog(int id) 
{
    switch (id) 
    {
    case 0:
        // This example shows how to add a custom layout to an AlertDialog
        android.app.AlertDialog.Builder login = new android.app.AlertDialog.Builder(this);

        try
        {

            LayoutInflater factory = LayoutInflater.from(this);
            final View textEntryView = factory.inflate(R.layout.login_dialog, null);

            final EditText username_alert = (EditText) textEntryView.findViewById(R.id.username);
            final EditText password_alert = (EditText) textEntryView.findViewById(R.id.password);

            login.setTitle("Login").setIcon(R.drawable.ic_launcher).setView(textEntryView)

            .setPositiveButton("Login", new DialogInterface.OnClickListener()
            {
                public void onClick(DialogInterface dialog, int whichButton) 
                {
                    /* User clicked OK so do some stuff */
                    String uname_alert=username_alert.getText().toString();
                    String pass_alert=password_alert.getText().toString();

                    if(uname_alert.equals("aaaa") && pass_alert.equals("aaaa"))
                    {
                        //do Something........
                    }
                    else
                    {
                        showDialog(0);
                    }
                }
            })
            .setNegativeButton("Cancel", new DialogInterface.OnClickListener() 
            {
                public void onClick(DialogInterface dialog, int whichButton) 
                {
                    /* User clicked cancel so do some stuff */
                }
            });
        }
        catch(Exception e)
        {
            e.printStackTrace();
        }
        return login.create();
    }
    return null;
}
  }

希望我的问题很清楚…… 。
请帮助我..
在此先感谢.....：）

Hope my question is clear....... Please help me .. Thanks in Advance ..... :)

推荐答案

I知道这个软件迟到了。但是对于未来的追求者。
我遇到了同样的问题，没有与.hide（）.show（）和.dismiss（）的组合不起作用。

I know this answare is late. But for the future seekers. I had the same problem and no combination with .hide() .show() and .dismiss() doesn't react. Probably the system need some time and then it is working fine.

if (!SDCartConnected())
{
        Handler handler = new Handler(); 
        handler.postDelayed(new Runnable(){
            public void run() {
                showDialog(Const.DIALOG_SDCARD_MISSING);}}, 2000);  
}

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