提取字符串中每个其他单词的算法？ [英] Algorithm to take out every other word in a string?

问题描述

在Javascript中，如果我有这样的字符串：你好，很高兴认识你
我想还给我的是奇怪的地方，所以我会得到：你好

In Javascript, if I have a string like so: "Hello nice to meet you" And what I would like returned to me are the words in odd places so I would get: "Hello to you"

我如何为此编写代码？

推荐答案

您可以使用 过滤器 创建一个新数组，其中的元素具有偶数索引。

You can use filter to create a new array with elements that have an even index.

只需记住，奇数位置的单词实际上位于偶数索引，因为javascript中的数组是零索引的。

Just remember that the words in "odd" places are actually located at even indexes, since arrays in javascript are zero-indexed.

var s = 'Hello nice to meet you'

var evenWords = (s) => s.split(' ').filter((element, index) => index % 2 === 0).join(' ');

console.log(evenWords(s))

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