字的最大频率值 [英] Maximum frequency value for word

问题描述

寻求家庭作业帮助

我得到一个列表，并要求其在列表中查找最常出现的值并返回次发生。这个问题相当大，我自己一个人就可以解决其他问题，但这让我很沮丧。我还要补充一点，这是一项对任何指导都值得赞赏的任务。

I am given a list and asked to find the most occurring value in a list and returns the amount of times it is occurred. This question is fairly big and i have managed to get through the other parts by myself but this one stumped me.I should add that this is for an assignment any guidance would be appreciated.

问题陈述：最大（单词）频率

例如，在带有以下单词 [' big， big， bat， bob， book] 最大频率为2，即big是最频繁出现的单词，因此2为最大频率。 / p>

For example in a book with the following words ['big', 'big', 'bat', 'bob', 'book'] the maximum frequency is 2, i.e., big is the most frequently occurring word, therefore 2 is the maximum frequency.

def maximum_frequency(new_list):

    word_counter = {}

    for word in new_list:

        if word in word_counter:

            word_counter[word] += 1

        else:

            word_counter[word] = 1

我已经走了这么远，但我不确定它是否正确/在哪里从这里开始

I have gotten this far but I am not sure if its right/where to go from here

推荐答案

如何操作：

def maximum_frequency(new_list):
    word_counter = {}
    for word in new_list:
        if word in word_counter:
            word_counter[word] += 1
        else:
            word_counter[word] = 1

    max_freq = max(word_counter.items(), key=(lambda x: x[1]))
    return max_freq


if __name__ == '__main__':
    test_data = ['big', 'big', 'bat', 'bob', 'book']
    print(maximum_frequency(test_data))

输出：

('big', 2)

在Python 2和3上运行良好并返回结果，将其作为最常见单词和出现次数的元组。

Works fine with Python 2 and 3 and returns result as a tuple of most frequent word and occurrences count.

编辑：

如果您不这样做，完全不关心哪个单词具有最高的计数，而您只想要可以将其简化的频率数字即可：

If you don't care at all which word has the highest count and you want only the frequency number you can simplify it a bit to:

def maximum_frequency(new_list):
    word_counter = {}
    for word in new_list:
       if word in word_counter:
            word_counter[word] += 1
        else:
            word_counter[word] = 1

    return max(word_counter.values())


if __name__ == '__main__':
    test_data = ['big', 'big', 'bat', 'bob', 'book']
    print(maximum_frequency(test_data))

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