为什么_mm256_load_pd编译为MOVUPD而不是MOVAPD？ [英] Why _mm256_load_pd compiled to MOVUPD instead of MOVAPD?

问题描述

为什么下面的代码导致未对齐的AVX指令（MOVUPD而不是MOVAPD）？我在Visual Studio 2015上进行了编译。如何告诉编译器我的数据确实对齐？

Why the following code results unaligned AVX instructions ( MOVUPD instead of MOVAPD)? I compiled this on Visual Studio 2015. How can I tell the compiler that my data is indeed aligned?

    const size_t ALIGN_SIZE = 64;
    const size_t ARRAY_SIZE = 1024;

    double __declspec(align(ALIGN_SIZE)) a[ARRAY_SIZE];
    double __declspec(align(ALIGN_SIZE)) b[ARRAY_SIZE];

    //Calculate the dotproduct
    __m256d ymm0 = _mm256_set1_pd(0.0);
    for (int i = 0; i < ARRAY_SIZE; i += 8)
    {
        __m256d ymm1 = _mm256_load_pd(a + i); 
        __m256d ymm2 = _mm256_load_pd(b + i);
        __m256d ymm3 = _mm256_mul_pd(ymm1, ymm2);
        ymm0 = _mm256_add_pd(ymm3, ymm0);

        __m256d ymm4 = _mm256_load_pd(a + i + 4);
        __m256d ymm5 = _mm256_load_pd(b + i + 4);
        __m256d ymm6 = _mm256_mul_pd(ymm4, ymm5);
        ymm0 = _mm256_add_pd(ymm6, ymm0);
    }



Assembly of the loop: 
00007FF7AC7A1400  vmovupd     ymm1,ymmword ptr [rbp+rax*8+2020h]  
00007FF7AC7A1409  vmulpd      ymm3,ymm1,ymmword ptr [rbp+rax*8+20h]  
00007FF7AC7A140F  vmovupd     ymm2,ymmword ptr [rbp+rax*8]  
00007FF7AC7A1415  vmulpd      ymm0,ymm2,ymmword ptr b[rax*8]  
00007FF7AC7A141E  add         r8d,8  
00007FF7AC7A1422  movsxd      rax,r8d  
00007FF7AC7A1425  vaddpd      ymm1,ymm0,ymm4  
00007FF7AC7A1429  vaddpd      ymm4,ymm1,ymm3  
00007FF7AC7A142D  cmp         rax,400h  
00007FF7AC7A1433  jb          main+70h (07FF7AC7A1400h)  

推荐答案

有一种方法可以解决此问题（它允许使用指令VMOVDQA（MOVAPD的替代品）代替MOVUPD）：

There is the way to solve this problem (it allows to use instruction VMOVDQA (analogue of MOVAPD) instead of MOVUPD):

inline __m256d Load(const double * p)
{
#ifdef _MSC_VER
    return _mm256_castsi256_pd(_mm256_load_si256((__m256i*)p));
#else
    return _mm256_load_pd(p);
#endif
}

浮点类型的类似解决方案：

Analogous solution for float type:

inline __m256 Load(const float * p)
{
#ifdef _MSC_VER
    return _mm256_castsi256_ps(_mm256_load_si256((__m256i*)p));
#else
    return _mm256_load_ps(p);
#endif
}

但是为了欺骗Visual Studio编译器，您必须使用动态分配的指针。否则，编译器将不使用VMOVDQA指令。

But in order to cheat Visual Studio compiler you have to use dynamically allocated pointers. Otherwise compiler doesn't use VMOVDQA instruction.

#include <immintrin.h>

int main()
{
    float * ps = (float*)_mm_malloc(40, 32);
    double * pd = (double*)_mm_malloc(40, 32);

    __m256 s = Load(ps);
//00007FF79FF81325  vmovdqa     ymm1,ymmword ptr [rdi]  
    __m256d d = Load(pd);
//00007FF79FF8132F  vmovdqa     ymm0,ymmword ptr [rax]

    _mm256_storeu_ps(ps, s);
    _mm256_storeu_pd(pd, d);

    _mm_free(ps);
    _mm_free(pd);
}

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