使用JavaScript从Amazon URL抓取ASIN [英] scrape ASIN from amazon URL using javascript

问题描述

假设我有这样的Amazon产品URL

Assuming I have an Amazon product URL like so

http://www.amazon.com/Kindle-Wireless-Reading-Display-Generation/dp/B0015T963C/ref=amb_link_86123711_2?pf_rd_m=ATVPDKIKX0DER&pf_rd_s=center-1&pf_rd_r=0AY9N5GXRYHCADJP5P0V&pf_rd_t=101&pf_rd_p=500528151&pf_rd_i=507846

我怎么只刮擦 ASIN 使用JavaScript？
谢谢！

How could I scrape just the ASIN using javascript? Thanks!

推荐答案

Amazon的详细信息页面可以有几种形式，因此要彻底检查所有内容。这些都是等效的：

Amazon's detail pages can have several forms, so to be thorough you should check for them all. These are all equivalent:

http://www.amazon.com/Kindle-Wireless-Reading-Display-Generation/dp/B0015T963C

http://www.amazon.com/dp/B0015T963C

http://www.amazon.com/gp/product/B0015T963C

http：// www。 amazon.com/gp/product/glance/B0015T963C

它们总是看起来像这样：

They always look like either this or this:

http://www.amazon.com/<SEO STRING>/dp/<VIEW>/ASIN
http://www.amazon.com/gp/product/<VIEW>/ASIN

这应该做到：

var url = "http://www.amazon.com/Kindle-Wireless-Reading-Display-Generation/dp/B0015T963C";
var regex = RegExp("http://www.amazon.com/([\\w-]+/)?(dp|gp/product)/(\\w+/)?(\\w{10})");
m = url.match(regex);
if (m) { 
    alert("ASIN=" + m[4]);
}

这篇关于使用JavaScript从Amazon URL抓取ASIN的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！