未声明ALAsset valueForProperty：ALAssetPropertyLocation吗？ [英] ALAsset valueForProperty:ALAssetPropertyLocation undeclared?

问题描述

这似乎太简单了，或者可能只是让我感到困惑……或者我太累了，无法理性地思考。

This might seem too easy or maybe it's just confusing for me... Or maybe I'm too tired to think rationally.

我正试图用户已使用imagePickerController从相册中选择的UIImage的位置。

I am trying to get the location of an UIImage that has been selected by the user from the photo album using imagePickerController.

- (void)imagePickerController:(UIImagePickerController *)picker didFinishPickingMediaWithInfo:(NSDictionary *)info
{
    UIImage *pic = [info objectForKey:@"UIImagePickerControllerOriginalImage"];
    NSData *data = UIImageJPEGRepresentation(pic, 0.01f);
    UIImage *image1 = [UIImage imageWithData:data];
    bookmarkImage.image = image1;

    NSLog(@"new image size = %i", [data length]);

    NSURL *url = [info objectForKey:@"UIImagePickerControllerReferenceURL"];
    4NSLog(@"%@",url);

    ALAssetsLibraryAssetForURLResultBlock resultBlock = ^(ALAsset *myAsset){
        [myAsset valueForProperty:ALAssetPropertyLocation];
    };

    [self dismissModalViewControllerAnimated:YES];
}

现在，我尝试在其中调用 valueForProperty 因为ALAsset是我遇到的麻烦。这是我遇到的错误：

Now, where I try to call the valueForProperty for ALAsset is where I have trouble. This is the error I'm getting:

使用未声明的标识符 ALAssetPropertyLocation。

Use of undeclared identifier 'ALAssetPropertyLocation'.

请帮助！这真令人沮丧...我需要照片的位置...

Please help! This is getting really frustrating... I need the location of the photo...

推荐答案

这很傻，但是我已经缺少导入内容：

It's pretty silly but I've been missing an import:

#import <AssetsLibrary/ALAsset.h>

感谢Markus指出了这一点！

Thanks to markus who pointed it out!

这篇关于未声明ALAsset valueForProperty：ALAssetPropertyLocation吗？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！