我总是看到“ E ActivityManager：从系统发送不受保护的广播”在android 7中是什么意思？ [英] I always see "E ActivityManager: Sending non-protected broadcast from system" in android 7. What does this mean?

问题描述

我正在尝试使用以下功能从非系统应用发送意图。

I am trying to send an intent from a non system app using the following function.

public static void sendIntent() {
        if (null != _context) {
            Intent intent = new Intent("com.test.testApp.testIntent");
            intent.setPackage(_context.getPackageName());
            _context.sendBroadcast(intent);
        }
    }

但是我总是看到来自ActivityManager的错误消息如下。相同的Intent Broadcast（app）在Andorid 6.0中工作正常，但在android 7.1.1中引发错误。我需要为android 7.1.1更改任何内容吗？

But I always see there is an error message from ActivityManager as below. The same intent broadcasting(app) works fine in andorid 6.0 but throws an error in android 7.1.1. I am required to change anything for android 7.1.1?

4-10 15：06：34.423 1615 2921 E ActivityManager：发送不受保护的广播com.test.testApp来自系统2886的.testIntent：com.test.testApp / u0a117 pkg com.test.testApp

4-10 15:06:34.423 1615 2921 E ActivityManager: Sending non-protected broadcast com.test.testApp.testIntent from system 2886:com.test.testApp/u0a117 pkg com.test.testApp

在ListFragment中，我按以下方式注册接收者：

In a ListFragment I register the receiver as follows:

 @Override
    public void onStart() {
        super.onStart();
        getActivity().registerReceiver((receiver),
                new IntentFilter(com.test.testApp.testIntent));
        TextView textDownload = (TextView) getActivity().findViewById(R.id.output);
        textDownload.setVisibility(android.view.View.INVISIBLE);
    }

推荐答案

这可能会有帮助，

如果您在AndroidManifest.xml中声明了 android：sharedUserId = android.uid.system，则声明受保护的广播。

If you have in your AndroidManifest.xml declared "android:sharedUserId="android.uid.system", then declare the protected broadcast.

参考资料： https://stackoverflow.com/a/50240471

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