单击切换开关后，MapView无法返回正常状态 [英] MapView not returning to normal state after clicking toggle switch

问题描述

当我将片段中的开关滑动到OFF位置时，我试图使地图视图恢复为正常样式，但它不起作用。以下是我所面对的过程中发生的事情：

I'm trying to get my map view to return to the normal style when I flick the switch within my fragment to the the OFF position but it's not working. The following is what occurs during the process that I am facing:

1. 碎片（污染地图）和开关出现


2. 轻弹开关切换到ON位置


3. 出现样式化地图


4. 轻弹开关切换到OFF位置


5. 地图不变

1. Fragment (containg map) and switch appeared
2. Flicked switch to ON position
3. Styled map appeared
4. Flicked switch to OFF position
5. Map doesn't change

我尝试使用 mGoogleMap.setMapType（GoogleMap.MAP_TYPE_NORMAL）; ，但是当我轻按开关时，地图仍然停留在样式化的地图视图上。不确定什么地方出了问题。解决此问题必须做什么？

I tried using mGoogleMap.setMapType(GoogleMap.MAP_TYPE_NORMAL); but the map still remains stuck on the styled map view when I flick the switch. Not really sure as to what has gone wrong. What must be done to resolve this problem?

public class FragmentMap extends android.support.v4.app.Fragment implements OnMapReadyCallback {

    private SwitchCompat swt;

    public FragmentMap() {
    }

    GoogleMap mGoogleMap;
    MapView mMapView;

    @Override
    public View onCreateView(LayoutInflater inflater, @Nullable ViewGroup container, @Nullable Bundle savedInstanceState) {
        View v = inflater.inflate(R.layout.fragment_map, container, false);

        mMapView = (MapView) v.findViewById(R.id.map_park);
        mMapView.onCreate(savedInstanceState);
        mMapView.getMapAsync(this);

        swt = (SwitchCompat) v.findViewById(R.id.switch_map_park);
        swt.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
            @Override
            public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
                if(isChecked){
                    boolean success = mGoogleMap.setMapStyle(new MapStyleOptions(getResources()
                            .getString(R.string.style_json)));

                    if (!success) {
                        Log.e("TabFragmentMap", "Style parsing failed.");
                    }
                }else{
                    // What goes here?
                    mGoogleMap.setMapType(GoogleMap.MAP_TYPE_NORMAL);
                }
            }
        });

        return v;
    }

    @Override
    public void onMapReady(GoogleMap googleMap) {
        mGoogleMap = googleMap;
        mGoogleMap.getUiSettings().setZoomControlsEnabled(true);
        mGoogleMap.setBuildingsEnabled(true);
        mGoogleMap.setMapType(GoogleMap.MAP_TYPE_NORMAL);
    }

    @Override
    public void onResume() {
        super.onResume();
        mMapView.onResume();
    }

    @Override
    public void onPause() {
        super.onPause();
        mMapView.onPause();
    }

    @Override
    public void onDestroy() {
        super.onDestroy();
        mMapView.onDestroy();
    }

    @Override
    public void onSaveInstanceState(Bundle outState) {
        super.onSaveInstanceState(outState);
        mMapView.onSaveInstanceState(outState);
    }

    @Override
    public void onLowMemory() {
        super.onLowMemory();
        mMapView.onLowMemory();
    }
}

推荐答案

在您的 else 代码，您正在使用 setMapType ，而您应该使用 setMapStyle 带有 null 参数以清除先前设置的样式，如此处。

In your else code, you are using setMapType while you should be using setMapStyle with a null parameter to clear the previously set styling, as mentioned here.

设置为null可清除以前的任何自定义样式。

Set to null to clear any previous custom styling.

代码应该像这样：

        @Override
        public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
            if(isChecked){
                boolean success = mGoogleMap.setMapStyle(new MapStyleOptions(getResources()
                        .getString(R.string.style_json)));

                if (!success) {
                    Log.e("TabFragmentMap", "Style parsing failed.");
                }
            }else{
                boolean success = mGoogleMap.setMapStyle(null);

                if (!success) {
                    Log.e("TabFragmentMap", "Removing style failed.");
                }
            }
        }

您还应该返回在您的 if（！success）条件下都切换到先前的检查状态，并显示向用户敬酒，使他们可以了解正在发生的事情。

You should also return the Switch back to its previous checked state in both your if (!success) conditions and show a Toast to the users so they can understand what is happening.

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