Bash：使用其他用户获取进程的pid [英] Bash: Get pid of a process using a different user

问题描述

我在bash中有一个脚本来启动Java程序，我想在执行后获取程序的pid。 pid将保存在文本文件中。

I have a script in bash to start a java program and I want to get the pid of the program after it executes. The pid will be saved in a text file.

现在，我有这样的内容：

Right now I have something like this:

if [ "$USER" == "root" ]
then
    su $APP_USER -c "nohup java $JAVA_OPTS  >> $LOG_OUT 2>> $LOG_ERR &"
    su $APP_USER -c "echo $! > $PID_PATH/$CAT.pid"
else
    nohup java $JAVA_OPTS >> $LOG_OUT 2>> $LOG_ERR &
    echo $! > "$PID_PATH/$CAT.pid"
fi

我也尝试过这样做，但是

I also tried like this but it doesn't work neither.

if [ "$USER" == "root" ]
then
    su $APP_USER -c "(nohup java $JAVA_OPTS  >> $LOG_OUT 2>> $LOG_ERR &); (echo $! > $PID_PATH/$CAT.pid)"
else
    nohup java $JAVA_OPTS >> $LOG_OUT 2>> $LOG_ERR &
    echo $! > "$PID_PATH/$CAT.pid"
fi

当我以APP_USER身份运行时，当我以root用户身份运行时，我的java程序启动但pid文件创建为空，效果很好。

when I run as my APP_USER all works great, when I run as root my java program starts but the pid file is created empty.

推荐答案

尝试

su $APP_USER -c "nohup java $JAVA_OPTS  >> $LOG_OUT 2>> $LOG_ERR & echo \$! > $PID_PATH/$CAT.pid"

\ $！后面的$ c>可以防止变量扩展，然后再传递给su命令。

\ behind $! prevents expansion of the variable, before passing to the su command.

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