如何在单个函数中接受& str,String和& String? [英] How to accept &str, String and &String in a single function?

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问题描述

我想编写一个函数,该函数接受& str String 和借用的& String 。我已经编写了以下2个函数:

I want to write a single function, that accepts a &str, a String and a borrowed &String. I've written the following 2 functions:

fn accept_str_and_ref_string(value: &str) {
    println!("value: {}", value);
}

fn accept_str_and_string<S: Into<String>>(value: S) {
    let string_value: String = value.into();
    println!("string_value: {}", string_value);
}

fn main() {
    let str_foo = "foo";
    let string_foo = String::from("foo");

    accept_str_and_ref_string(str_foo);
    accept_str_and_ref_string(&string_foo);

    accept_str_and_string(str_foo);
    accept_str_and_string(string_foo);
}

是否可以实现一个功能,这样我就可以做到:

Is it possible to implement one function so that I can do this:

accept_all_strings(str_foo);
accept_all_strings(&string_foo);
accept_all_strings(string_foo);


推荐答案

您可以使用 AsRef< str> 特征:

You can use the AsRef<str> trait:

// will accept any object that implements AsRef<str>
fn print<S: AsRef<str>>(stringlike: S) {
    // call as_ref() to get a &str
    let str_ref = stringlike.as_ref();

    println!("got: {:?}", str_ref)
}

fn main() {
    let a: &str = "str";
    let b: String = String::from("String");
    let c: &String = &b;

    print(a);
    print(c);
    print(b);
}

print 函数将支持实现 AsRef< str> 的任何类型,其中包括& str String & String

The print function will support any type that implements AsRef<str>, which includes &str, String and &String.

这篇关于如何在单个函数中接受&amp; str,String和&amp; String?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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