对包含一些特殊字符的URL的处理方式 [英] What you would do to a URL that contains some special characters

问题描述

我正在使用cakePHP 1.26

我得到了一个包含URL的输入文本框，我想提交该URL并使用Jquery AJAX将其存储在数据库中。

I am using cakePHP 1.26
I got an Input Text box which contains a URL and I want to submit the URL and stored it in the Database using Jquery AJAX.

以下是HTML部分：

Here is the HTML part:

<input type="text" id="testing" value="https://stackoverflow.com/questions/ask">

这是JQuery的一部分：

This is the JQuery part:

  var whatContent=$("#testing").val();
      var curl="http://localhost:8080/test/grab/"+whatContent;
      $.ajax({
      type: "POST",
      url: curl,   
      success: function(data) {    
      alert(data);}
      });

这是控制器中操作的代码：

This is the code for the Action in the Controller:

function grab($w=null){
   if($w!=null){
     return $w;
    }
}

代码有效，我可以看到警报消息弹出向上，但显示：
https://stackoverflow.com/

而不是

https://stackoverflow.com/questions/ask

The code worked and I could see the Alert Message pop up, but it showed: https://stackoverflow.com/
instead of
https://stackoverflow.com/questions/ask

我曾尝试使用转义（whatContent）和encodeURI（whatContent），但它们无济于事，

警报框仍向我显示
https://stackoverflow.com/

代替了

https://stackoverflow.com/questions/ask

I have tried using escape(whatContent), and encodeURI(whatContent), but they could not help,
the Alert box still showed me https://stackoverflow.com/
instead of
https://stackoverflow.com/questions/ask

我不确定该怎么做

I am not sure how to do with the URL data that contains some special characters in it.

推荐答案

也许是 debug（$ w） 在您的控制器操作中可能会显示一些内容。
除了目标地址之外，其他输入的输出是什么？

Maybe a debug($w) in you controller action could reveal something. What is the output of other input than the address that is your goal?

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