CATALINA_HOME环境变量未正确定义 [英] CATALINA_HOME environmental variable is not defined correctly

问题描述

我将Apache Tomcat 6.0安装到 C：/ Program Files 文件夹，并设置环境变量 JAVA_HOME 和 CATALINA_HOME ，但是当我使用 startup.bat 启动服务器时，出现错误：

CATALINA_HOME环境变量未正确定义。

我的 CATALINA_HOME 环境变量设置为 CATALINA_HOME = C：\Program Files\apache-tomcat-6.0.35 。 / p>

我做错了什么？

解决方案

首先，您必须提及tomcat，直到tomcat的版本，请参见以下

CATALINA_HOME：C：\Program Files\apache-tomcat-6.0.35;
然后将CLASSPATH变量设置为

CLASSPATH：C：\Program Files\apache-tomcat-6.0.35\lib;

然后最后将路径变量编辑为
PATH：。;％CATALINA_HOME％\bin;

注意：必须在每个变量的末尾添加分号（;）。

I installed Apache Tomcat 6.0 to a C:/Program Files folder and I set the environmental variables JAVA_HOME and CATALINA_HOME, but when I start the server using startup.bat, I am getting the error:

CATALINA_HOME environmental variable is not defined correctly.

My CATALINA_HOME environment variable is set to CATALINA_HOME=C:\Program Files\apache-tomcat-6.0.35.

What did I do wrong?

解决方案

At first you have to mention tomcat up to tomcat's version refer below

CATALINA_HOME: C:\Program Files\apache-tomcat-6.0.35; then set CLASSPATH variable to

CLASSPATH : C:\Program Files\apache-tomcat-6.0.35\lib;

then finally edit path variable to PATH: .;%CATALINA_HOME%\bin;

NOTE: a semicolon(;) must be put at the end of each and every variable.

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