在python中的迭代器/生成器中引发异常后继续 [英] Continue after exception raising in iterator/generator in python

问题描述

在迭代器/生成器抛出异常之后，Python中是否有任何方法可以继续迭代？就像下面的代码一样，有什么方法可以跳过ZeroDivisionError并继续循环遍历 gener（）而无需修改 run（）

Is there any way in Python to continue iterating after exception throwed by iterator/generator? Like in code below, is there any way to skip ZeroDivisionError and continue looping through gener() without modyfying run() function?

def gener():
    a = [1,2,3,4,0, 5, 6,7, 8, 0, 9]
    for i in a:
        yield 2/i

def run():
    for i in gener():
        print i

#---- run script ----#

try:
    run()
except ZeroDivisionError:
    print 'what magick should i put here?'

推荐答案

try / except 的逻辑位置将是进行违规计算的位置：

The logical place for the try/except would be the place where the offending calculation takes place:

def gener():
    a = [1,2,3,4,0, 5, 6,7, 8, 0, 9]
    for i in a:
        try:
            yield 2/i
        except ZeroDivisionError:
            pass

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