Java编程异常 [英] Java programming exception

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本文介绍了Java编程异常的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

有人可以帮助我吗?我不理解此异常:

Can any one help me? I do not understand this exception:

Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: 9
    at java.lang.String.charAt(Unknown Source)
    at charPerLine.main(charPerLine.java:13)

这是负责的代码:

import java.util.*;
public class charPerLine {

    public static void main(String[] args)throws StringIndexOutOfBoundsException {
        Scanner sc=new Scanner(System.in);
        System.out.print("Type any name:");
        String s=sc.next();
        int j= s.length()+1;
        for(int i=0;i<=j;i++){
            System.out.println(s.charAt(i));
        }
    }
}


推荐答案

您试图直接访问少于10个字符的字符串的第10个字符。像这样的东西:

You're trying to directly access the 10th character of a string which has less than 10 characters. Something like:

"12345".charAt(9)

请记住,字符串索引基于0,因此 .charAt(9) =>第10个字符。因此 123 .charAt(3)也会抛出。

Remember that String indices are 0-based, hence .charAt(9) => 10th character. So "123".charAt(3) would throw, too.

这篇关于Java编程异常的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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