引发异常时是否可以自动闯入调试器？ [英] Is it possible to automatically break into the debugger when a exception is thrown?

问题描述

如果有人在最​​初抛出的函数之外捕获到异常，则有人将无法访问本地堆栈。结果，无法检查可能导致异常的变量的值。

If ones catches an exception outside of the function it is originally thrown, ones loses access to the local stack. As a result one cannot inspect the values of the variables that might have caused the exception.

是否有一种方法可以随时自动启动调试器（ import pdb; pdb.set_trace（））

Is there a way to automatically start break into the debugger (import pdb; pdb.set_trace()) whenever a exception is thrown to inspect the local stack?

推荐答案

我发现我在寻找使用Python pdb检查未处理异常原因的最简单方法是什么？

用以下代码包装：

Wrap it with that:

<!-- language: lang-py -->
def debug_on(*exceptions):
    if not exceptions:
        exceptions = (AssertionError, )
    def decorator(f):
        @functools.wraps(f)
        def wrapper(*args, **kwargs):
            try:
                return f(*args, **kwargs)
            except exceptions:
                pdb.post_mortem(sys.exc_info()[2])
        return wrapper
    return decorator

示例：

@debug_on(TypeError)
def buggy_function()
    ....
    raise TypeError

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