Python 3异常：TypeError：函数缺少1个必需的位置参数：'words' [英] Python 3 Exception: TypeError: function missing 1 required positional argument: 'words'

问题描述

我的函数需要一个参数单词，但我希望程序在没有参数的情况下也不会崩溃。

My function needs one argument words, but i want the program not to crash if no argument.

def get_count(words):
    try:
        consonants_str = "bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ"
        vowels_str = "aeiouAEIOU"
        consonants_ls = []
        vowels_ls = []
        words_ls = []
        result = {"vowels": 0, "consonants": 0}`

        for element in consonants_str:
            consonants_ls.append(element)

        for element in vowels_str:
            vowels_ls.append(element)

        if type(words) != type(None):
            for element in words:
                words_ls.append(element)

            for element in words_ls:
                if element in vowels_ls:
                    result["vowels"] += 1
                if element in consonants_ls:
                    result["consonants"] += 1
                else:
                    continue
            else:
                result["vowels"] = 0
                result["consonants"] = 0

    except TypeError:
        result["vowels"] = 0
        result["consonants"] = 0

    answer = {"vowels": result["vowels"],"consonants": result["consonants"]}

    return answer`

因此，如果我使用

print(get_count())

我想要的是，该程序不会向我显示类似于标题中的错误。例外应该在 get_count 的 def 中，因为它应该是封闭文件。我不在同一个文件中执行，因此Exception应该独立于其他文件。

I want, that the program doesn't show me an error like the one in the heading. The exception for that should be in the def of get_count because it should be a closed file. I don't execute in the same file, so the Exception should be independent from other files.

希望您能理解我的意思...

I hope you understand what I mean...

感谢您的回答！
NoAbL

Thanks for your answers! NoAbL

推荐答案

当您声明要使用名为 words 和 def（words），像这样或您需要的任何字符串输入调用函数

You're not passing an argument to your function, when you declared that you want an argument named words with def(words), call your function like this or with any string input you desire

print(get_count('AAAABBBKDKDKDKDA'))

如果您希望在不传递任何参数时退出程序，请执行此操作（记住单词现在是一个元组）

if you want the program to exit when no argument is passed, do this (remember words is now a tuple)

import sys

def get_count(*words):
    if not words: # if words is empty, no argument was passed
        sys.exit('You passed in no arguments')
    else:
        pass # do something with the items in words

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