如何在Worker API中检测无效URL的错误 [英] How to detect errors of invalid URL in Worker API

问题描述

如果我运行以下命令（至少在Chromium上运行）：

If I run the following (at least on Chromium):

var w = null;
try {
    w = new Worker( 'NONEXISTENT_URL' );
}
catch ( e ) {
    console.log( 'CAUGHT: ' + e );
}
console.log( w );

...即使 Worker 构造函数未指向到有效的文件名。此外，控制台显示 Worker {} ，指示 w 现在包含<$的（非功能性）实例。 c $ c> Worker 。

...no exception is caught, even though the argument to the Worker constructor does not point to a valid filename. Moreover, the console shows Worker {}, indicating that w now holds a (non-functional) instance of Worker.

其他错误情况也是可能的。例如，构造函数的参数可能可用并且可读，但其中不包含有效的JavaScript。

Other error conditions are also possible. For example, argument to the constructor may be available and readable, but not contain valid JavaScript.

我还能如何检测到此类错误情况？

How else can I detect such error conditions?

（顺便说一句，请假定浏览器支持 Worker API。）

(BTW: Please assume that the browser supports the Worker API.)

推荐答案

使用 onerror 事件处理程序。

You can get error using onerror event handler.

var worker = new Worker('aURL');

worker.onerror = function () {
    console.log( 'error' );
};

如果URL的语法无效或同源策略违反了抛出SECURITY_ERR类型的 DOMException 。

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