Java跳过尝试捕获以抛出功能 [英] Java skip try catch for throwable fuction

问题描述

我想知道Java中是否有一种方法可以跳过我认为不会抛出异常的可抛出函数的try-catch方法。

I wonder if there is a way in Java to 'skip' the try-catch method for a throwable function that I know will not throw an exception.

I拥有这段代码：

DateFormat format = new SimpleDateFormat("yyyy-MM-dd HH:mm");
Date date = format.parse(dateString); // <-- Compiler error here
Log.i(PF.TAG, date.toString());

我收到编译器错误，指出未处理异常

I get compiler error saying an exception is not handled

错误：（97，30）错误：未报告的异常ParseException;必须被捕获或声明为被抛出

Error:(97, 30) error: unreported exception ParseException; must be caught or declared to be thrown

我可以通过放置 format.parse来消除此错误（）在try-catch中。

I can get rid of this error by putting the format.parse() inside a try-catch.

在Swift 2错误处理中，有一个选项可以进行 try！ someFunction（）将编译并执行throwable函数，如果发生错误则崩溃。

In Swift 2 error handling there is an option to do try! someFunction() which will compile and execute the throwable function and crash if there is an error.

在Java中是否有类似的方法，所以我

Is there a similar way in Java so I dont have to put all the small tasks which I know will not throw an exception in a try-catch everywhere?

推荐答案

不是真的要把所有我知道不会在任何地方的异常都放入try-catch中的小任务吗？ ，但是您可以编写一个辅助方法来欺骗编译器，使他们认为未检查的异常是未检查的。例如：

Not really, but you can write a helper method to trick the compiler into believing that the checked exception is unchecked. For example:

public static <T> T uncheck(Callable<T> callable) {
  try {
    return callable.call();
  } catch (Throwable t) {
    return rethrow(t);
  }
}

@SuppressWarnings("unchecked")
private static <E extends Throwable, T> T rethrow(Throwable t) throws E {
  throw (E) t;
}

您将像这样使用它：

Date date = uncheck(() -> format.parse(dateString));

您还可以将已检查的异常包装为未检查的异常，例如jOOL所做的此处。

You could also wrap the checked exception into an unchecked exception, like what jOOL does here.

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