为什么抛出IndexOutOfBoundsException？ [英] Why is IndexOutOfBoundsException Thrown?

问题描述

为什么在以下代码段中引发IndexOutOfBoundsException？
我似乎不明白为什么会抛出它？

Why is the IndexOutOfBoundsException thrown in the following code segment? I can’t seem to understand why it is thrown?

    import java.util.*;
    public class PrimeNumbers {

        //Printing all prime numbers less than 600 using 'Sieve Method'
        final static int SIZE = 600;
        static ArrayList<Integer> numbers = new ArrayList<Integer>(SIZE);


        public static void populateList(ArrayList<Integer> arraylist){
            for(int i=0; i<SIZE; i++){
                arraylist.add(i, i);
            }
        }

        public static void filterMultiples(ArrayList<Integer> arraylist){
            for(int i=0; i<SIZE; i++){
                if(arraylist.get(i)%2==0 || arraylist.get(i)%3==0 || arraylist.get(i)%5==0){
                    arraylist.remove(i);
                    }
                }
            }

        public static void main(String[] args){
            populateList(numbers);
            filterMultiples(numbers);
            System.out.println(numbers);

        }
    }

堆栈跟踪：

Exception in thread "main" java.lang.IndexOutOfBoundsException: Index: 300, Size: 300
at java.util.ArrayList.rangeCheck(ArrayList.java:653)
at java.util.ArrayList.get(ArrayList.java:429)
at PrimeNumbers.filterMultiples(PrimeNumbers.java:17)
at PrimeNumbers.main(PrimeNumbers.java:25)

推荐答案

for(int i=0; i<SIZE; i++){
    if(arraylist.get(i)%2==0 || arraylist.get(i)%3==0 || arraylist.get(i)%5==0){
        arraylist.remove(i);
        }
    }
}

您从0开始迭代到 SIZE ，但是删除元素将导致列表中少于 SIZE 个元素。

You're iterating from 0 to SIZE, but removing elements will cause there to be fewer than SIZE elements in the list.

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