Rails 5-为模型的每个实例创建虚荣路线 [英] Rails 5 - Create vanity route for each instance of model

问题描述

我知道必须有一种更清洁的方式来执行此操作，但是我已经有一段时间没有编写代码了，并且正在绘制空白。

I know there has to be a cleaner way of doing this but I haven't written code in a while and am drawing a blank.

我有一个名为Link的模型，其中包含Title，Slug和Destination。目标是要重定向的位置（mydomain.com/instagram将重定向到我的instagram帐户）。 Slug是为friendly_id自定义Slug。

I have a model called Link that has a Title, Slug and Destination. Destination is the location to redirect (mydomain.com/instagram would redirect to my instagram account). Slug is to customize the slug for friendly_id. This is the code in my routes.rb and it works but it feels gross.

Link.all.each do |link|
  get "/#{link.slug}", to: 'links#show', :id -> link.id
end

是否有更好的方法来完成此任务？

Is there a better way to accomplish this task?

推荐答案

您可以使用单个操作和路由来匹配所有链接，例如。

You can use single action and route to match all of your links like that.

在route.rb的bttom处

At bttom of routes.rb

get '*id', :to => 'links#show'

在links_controller.rb中

in links_controller.rb

  def show
    @link = Link.find_by_slug(params[:id])
  end

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