如何在本机反应中创建可搜索的下拉列表以打开特定屏幕？ [英] How to make a searchable droplist in react native to open an specific screen?

问题描述

我正在尝试使用列表，下拉列表，
创建搜索栏

I'm trying to make a search bar with a list,dropdown list,

如何通过以下代码创建搜索列表：

how to make a search list lik this code:

 onPress={() =>this.props.navigation.navigate('LinhaDiurno03')

何时按下项目？

....我希望列表中的每个项目在应用程序中打开一个不同的屏幕....

....I want that each item in the list open a different screen in the application....

我该怎么办？

这是我的遗嘱：

下拉列表中的代码

此处为某些代码：

 var items = [
  //name key is must.It is to show the text in front
  {id: 1, name: 'ANA RECH', prestadora: 'UNIDOS', pos: 'P01'},
  {id: 2, name: 'ARROIO DAS MARRECAS', prestadora: 'UNIDOS', pos: 'P01'},
  {id: 3, name: 'VILA SECA', prestadora: 'UNIDOS', pos: 'P01'},];

 onItemSelect={item => Alert.alert(" ", JSON.stringify(item.prestadora + ", LINHA: " + item.pos), [{ text: "open the especifc screen", onPress: () =>('some code here')},{ text: "bacvk", onPress: () => console.log("OK Pressed")}],{ cancelable: true })}
  //onItemSelect called after the selection from the dropdown

推荐答案

我阅读了库API，可以设置导航键，然后在 onItemSelect 中转到特殊屏幕。

I read the library API, you can set the navigation keys in the item, then in the onItemSelect to go to the special screen. the example code is below.

// in the item every element add a router key
const item = [
...
{
    id: 8,
    name: 'Swift',
    key:"the navigation params" //like the example LinhaDiurno03
  },
...
]

<SearchableDropdown
            multi={true}
            selectedItems={this.state.selectedItems}
            onItemSelect={(item) => {
              his.props.navigation.navigate(item.key)
            }}
/>

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