Django:使用模板继承时在基本模板文件中加载自定义过滤器时出现问题 [英] Django: problems while loading custom filters in the base template file while using template inheritance

问题描述

在模板中执行{% load custom_filters %}时，在{% extends "base.html" %}之后一切正常，但是当我将负载移至base.html模板时，过滤器就会出现怪异的行为.这是我的custom_filters.py:

When doing the {% load custom_filters %} in the template, after {% extends "base.html" %} everything works fine, but when I move the load to the base.html template the filter gets a weird behaviour. This is my custom_filters.py:

from django import template
from django.template.defaultfilters import stringfilter

register = template.Library()

# To cut off strings at a specified character, at first occurance. Example:
#   time = 19:30:12.123456
#   {{ time|cut:'.' }}
#   returns: 19:30:12
@register.filter
@stringfilter
def cut(string, cutoff_point):
    return string.split(cutoff_point, 1)[0]

当我将其加载到最终模板"中时，行为符合预期.如果time = 19:30:12.123456，则{{ time|cut:'.' }}返回19:30:12.当我将其加载到base.html中时，返回值是19:30:12123456，与输入相同，但没有截止点".

When I load it in the 'end-template' the behaviour is as expected. If time = 19:30:12.123456 then {{ time|cut:'.' }} returns 19:30:12. When I load it in base.html the returned value is 19:30:12123456, the same as the input but without the 'cutoff-point'.

有人知道为什么吗?

推荐答案

您应该在每个要使用自定义标记或过滤器的模板中放置{% load ... %}.

You should place {% load ... %} in every template, where you want to use your custom tag or filter.

对于您来说，调用过滤器cut也不是一个好主意，因为此过滤器已经存在(它已用于从字符串中切出一个点).

In your case it's also not a good idea to call a filter cut, because this filter already exists (and it's used to cut a dot from your string).

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